Behavior of Solve with $Assumptions changed in 12.2

Something changed with Solve between versions 12.1 and 12.2.

12.1:

Solve[n == n E^(r (1 - n)), n] (* Solve::ifun -- Inverse functions are being used by Solve, so some solutions may not be found; use Reduce for complete solution information. *) (* {{n -> 0}, {n -> 1}} *)  $  Assumptions = {n >= 0}; Solve[n == n E^(r (1 - n)), n] (* Solve::ifun -- Inverse functions are being used by Solve, so some solutions may not be found; use Reduce for complete solution information. *) (* {{n -> 0}, {n -> 1}} *) 

12.2:

Solve[n == n E^(r (1 - n)), n] (* Solve::ifun -- Inverse functions are being used by Solve, so some solutions may not be found; use Reduce for complete solution information. *) (* {{n -> 0}, {n -> 1}} *)  $  Assumptions = {n >= 0}; Solve[n == n E^(r (1 - n)), n] 

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Is this an improvement or a bug? It seems hard for the condition ConditionalExpression[1, Re[r] == 0 || Re[r] > 0 || Re[r] < 0] not to hold, but maybe I’m overlooking something.

Two work-arounds:

$  Assumptions = {n >= 0, r \[Element] Reals}; Solve[n == n E^(r (1 - n)), n]  Solve[n == n E^(r (1 - n)), n, Reals] 

both give {{n -> 0}, {n -> 1}} (no Solve::ifun either).

Another example, not fixable by including Reals:

$  Assumptions = {n1 >= 0, n2 >= 0}; Solve[0 == n1 (1 - n1 - 0.5 n2), n1] 

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