finding the combinatorial solutions of series and parallel nodes


I have n nodes, and I want to find the (non duplicate) number of possible ways in which these nodes can be combined in series and parallel, and also enumerate all the solutions. For example, for n=3, there are 19 possible combinations.

 0 (0, 1, 2)  1 (0, 2, 1)  2 (1, 2, 0)  3 (1, 0, 2)  4 (2, 0, 1)  5 (2, 1, 0)  6 [0, 1, 2]  7 [0, (1, 2)]  8 [0, (2, 1)]  9 (0, [1, 2]) 10 ([1, 2], 0) 11 [1, (0, 2)] 12 [1, (2, 0)] 13 (1, [0, 2]) 14 ([0, 2], 1) 15 [2, (0, 1)] 16 [2, (1, 0)] 17 (2, [0, 1]) 18 ([0, 1], 2) 

In the notation above, a series combination is denoted by (..) and a parallel combination is denoted by [..]. Duplicates are removed, for example [0,1,2] is the same as [1,2,0] since all of them are happening in parallel so the order does not matter here.

Can you give me an algorithm for this, or if any such algorithm already exists, then point me to it?

(I tried googling for a solution, but did not hit any relevant answer, maybe I was entering the wrong keywords.)

Note: for a sequential-only solution, the answer is easy, it is n!, and the enumeration of the solutions is also easy. But when parallelism (especially non duplicates) is added to the problem, it gets very complex.