How to alternate image on left/right using “Views Parity Row” module

This great tutorial explains everything except the CSS work.

I need to add CSS class to each row so I can set left/right alignment accordingly in css style. Views settings allows me to set the ccs class in Page: Style options but this one is always the same for each row. I need the class name also to alternate.

I need something like dynamically use the View Mode as css class name.

Current output: <div class="views-row"> Desired output: <div class="views-row left"> and <div class="views-row right">

Or am I missing something and the CSS work is done in a complete different way?

Alternate address to access

We use Google services to sign on to a range of Web Applications as contractors for a company. But they have locked this address and state that this address enables file sharing – which I’m pretty sure it doesn’t, it just enables you to login to another service that allows file sharing such as Google drive or Gmail. They previously had drive and Gmail locked, so I don’t have a problem with that. But we chose the remaining application we use for timesheets etc based on them providing Google sign in.

Probably a ridiculous question, but is there any other to authenticate to Google?

What are some alternate names for characters of Arthurian legend?

I’m working on a Homebrew world and have always thought the legends of King Arthur and the knights of the round table were cool. I planned on basing one of my kingdoms on them but didn’t want it to be immediately obvious that the characters are from the legends. I’m looking for alternate names that might hint at all the major characters and locations like Arthur, Merlin, Morgana, Lancelot, Mordred, Guinevere, Camelot, etc.

Alternate property of H^2(T, Z)

Let us take $ T = S^1_X \times S^1_Y$ , which is a torus, where the former $ S^1_X$ has the coordinate $ X$ , whereas the latter $ S^1_Y$ has $ Y$ . If we consider the generator $ dX \wedge dY \in H^2(T, {\Bbb R})$ , we have obviously the well-known relation $ dX \wedge dY = – dY \wedge dX$ , i.e. an alternate property.

By dual, $ H_2(T, {\Bbb R})$ must enjot the alternate property as well. This seems to consider $ S^1_X \times S^1_Y$ or $ S^1_Y \times S^1_X$ .

Q. How $ S^1_X \times S^1_Y$ is the minus of $ S^1_Y \times S^1_X$ in $ H_2(T, {\Bbb R})$ ?

Obviosuly, it is $ NOT$ easy to check this compared to visible differential forms.

Swapping alternate nodes of linkedlist

package main  import (     "fmt" )  type LinkedList struct {     first, last *node     }  type node struct {     item int     next *node  }  func (l *LinkedList) add (val int) {     n := node {         item: val,         next: nil,     }     if l.first == nil {         l.last = &n         l.first = &n     } else { = &n         l.last = &n     }     }  func (l *LinkedList) traverse () {     for n := l.first; n != nil; n = {         fmt.Printf("%v ", n.item)      }      fmt.Println()  }  func (l *LinkedList) swapLL () {     if l.first == nil {         panic("First element cannot be null")         }      if == nil {         return     }      ptr1 := l.first     var ptr2 *node     var ptr3 *node     var prev *node      for ; ptr1 != nil && != nil; {         //Allocate resources         ptr2 =         ptr3 =          //swap = ptr1 = ptr3          //hook to the previous pair         if prev == nil {             l.first = ptr2         } else {    = ptr2         }          //advance         prev = ptr1         ptr1 = ptr3     }  }  func main () {     l := LinkedList {         first: nil,         last: nil,     }      l.add(10)     l.add(20)     l.add(30)     l.add(40)      l.traverse()      l.swapLL()      l.traverse() } 

Question: Input Linkedlist: 10 -> 20 -> 30 -> 40 -> null Output Linkedlist: 20 -> 10 -> 40 -> 30 -> null

Here 10 and 20 are alternate/adjacent thus they were swapped. Here 30 and 40 are alternate/adjacent thus they were swapped.

I am looking for suggestions for improving my code, any optimizations, or anything to make my code more readable and elegant.

Are there alternate names for a “one touch expandable” split pane button?

A Java tutorial on split panes describes how the draggable split divider can be optionally configured with two small buttons that, with one click, can make the split pane show the entirety of the left or the right pane.

enter image description here

Two small arrows appear at the top of the divider in the example’s split pane. These arrows let the user collapse (and then expand) either of the components with a single click.

I still see this every now and then, like in the current release of Adobe Acrobat Reader DC where it is used for sidebars:

enter image description here

I’m trying to find a bit of UI information about this, but I am not coming up with anything in my searches, aside from Java examples. Does this button go by an alternate name?

Is this alternate version of the “Observant” Feat balanced?

I’m a DM and have a player who likes the Observant feat:

  • Increase your Intelligence or Wisdom score by 1, to a maximum of 20.
  • If you can see a creature’s mouth while it is speaking a language you understand, you can interpret what it’s saying by reading its lips.
  • You have a +5 bonus to your passive Wisdom (Perception) and passive Intelligence (Investigation) scores.

However, the player is concerned that it might be hard to remember when to apply the bonus and that the bonuses may be too situational (Only affects passives, references “passive Investigation” which I’ve never seen used).

To try to simplify things, I wrote a homebrew version of the Observant feat using UA’s Perceptive as a guideline:

  • Increase your Intelligence or Wisdom score by 1, to a maximum of 20.
  • You gain proficiency in the Perception skill. If you are already proficient in the skill, you add double your proficiency bonus to checks you make with it.
  • You gain proficiency in the Investigation skill. If you are already proficient in the skill, you add double your proficiency bonus to checks you make with it.

(Basically, it just grants proficiency/expertise for all Perception and Investigation checks rather than a single bonus for passive scores).

Is this feat effectively balanced with the original?

Alternate to nested if statements (alternate posing of question)

Sample Data Sheet:

The end goal is to have a Month + Year show up in a single cell, based on the first instance of “New Total” being >=0.

The sheet includes sample data, and the formatting we are interacting with.

In the purple box, I want the month + year to populate, based on the first instance of “New Total” being >=0. When the formula reaches the first instance of >=0 (March in the sample data), I want it to then pull “March” from cell Q2 and concatenate with “2019” from cell “S2”. The values of “New Total” are dynamic, and will change periodically. Right now, the sample data should result in “March 2019”, but tomorrow it might change so that “February” is the first >=0 instance.


Input: Row of Numbers, looking for the first instance of “New Total” being >=0.

Output: Pull Month + Year once “New Total” has found int >=0 in specified row. Display in specified cell.

Here’s how it was done with the nested IF statements:

=IF(G15>=0,E14&" "&G14,IF(J15>=0,H14&" "&J14,IF(M15>=0,K14&" "&M14, 

Where can I find LPJ Design’s alternate gun rules for Pathfinder?

From this answer:

Your main problem is that the Gunslinger is gimped by the awful Pathfinder gun rules. It will never have comparable damage to other characters. Consider getting your DM to allow better firearm rules, they exist in the Pathfinder Freeport Companion and Adamant Entertainment’s Tome of Secrets, and here’s a great free set of gun rules (I wrote) for Pathfinder from LPJ Design via RPGNow.

The link in that answer is dead. Where are LPJ Design’s alternate gun rules for Pathfinder available now?

Alternate to Nested IF statements

enter image description here

Goal here is to have the sheets search a row, then once it finds the first instance of >=0, return the cell value that contains the month+concatenate the value in the cell next to it (or any other cell of choice). I’ve confirmed I can do this with a series of nested IF statements, but am looking for something more efficient. I’m not too terribly familiar with writing my own scripts, but can if someone can give general direction.