## Can the Command spell force someone to answer a question in a Zone of Truth?

If you have an enemy in a Zone of Truth who failed their save, they can still choose to not answer. If a player casts Command on them with the word being "answer" would that force the creature to answer the question posed? Similarly, what if you cast the command "lie" on a creature in a Zone of Truth?

## How To Answer To Someone Saying D&D is stupid?

I’m a senior in a US high school, so people’s opinions are still very important to me. At my school, the board game club consists of like five people, and in the rest of the school, everyone thinks the game is for people who have never been in social interaction. I’m not socially awkward at all, and I don’t know how to answer someone saying it’s stupid or nerdy. Why do others think it’s nerdy, and how can I convince them it’s a good game?

## How can I correct this code to get an answer?

I need to calculate matrix m1 according to following algorithm. Then, I have to put it in the differential equation. However, matrix m1 is complex and therefore the differential equation does not work.
How can I correct this code to get an answer?

 m = {{0, WP[t], WP[t], WP[t], 0}, {WP[t], -FSR, 0, 0, -WS[t]}, {WP[t],  0, 0, 0, WS[t]}, {WP[t], 0, 0, FSR, -WS[t]}, {0, -WS[t],   WS[t], -WS[t], 0}};   q = Eigenvectors[m]; qq1 = Normalize[q[[1]]]; qq2 = Normalize[q[[2]]]; qq3 = Normalize[q[[3]]]; qq4 = Normalize[q[[4]]]; qq5 = Normalize[q[[5]]];   Ali1 = {{D[qq1, t][[1]], 0, 0, 0, 0}, {D[qq1, t][[2]], 0, 0, 0,    0}, {D[qq1, t][[3]], 0, 0, 0, 0}, {D[qq1, t][[4]], 0, 0, 0,    0}, {D[qq1, t][[5]], 0, 0, 0, 0}};  Vali1 = ConjugateTranspose[Ali1];  Kazi1 = Ali1.Vali1;   Ali2 = {{D[qq2, t][[1]], 0, 0, 0, 0}, {D[qq2, t][[2]], 0, 0, 0,    0}, {D[qq2, t][[3]], 0, 0, 0, 0}, {D[qq2, t][[4]], 0, 0, 0,    0}, {D[qq2, t][[5]], 0, 0, 0, 0}}; Vali2 = ConjugateTranspose[Ali2]; Kazi2 = Ali2.Vali2;  Ali3 = {{D[qq3, t][[1]], 0, 0, 0, 0}, {D[qq3, t][[2]], 0, 0, 0,  0}, {D[qq3, t][[3]], 0, 0, 0, 0}, {D[qq3, t][[4]], 0, 0, 0,  0}, {D[qq3, t][[5]], 0, 0, 0, 0}}; Vali3 = ConjugateTranspose[Ali3]; Kazi3 = Ali3.Vali3;  Ali4 = {{D[qq4, t][[1]], 0, 0, 0, 0}, {D[qq4, t][[2]], 0, 0, 0,  0}, {D[qq4, t][[3]], 0, 0, 0, 0}, {D[qq4, t][[4]], 0, 0, 0,  0}, {D[qq4, t][[5]], 0, 0, 0, 0}}; Vali4 = ConjugateTranspose[Ali4]; Kazi4 = Ali4.Vali4;   Ali5 = {{D[qq5, t][[1]], 0, 0, 0, 0}, {D[qq5, t][[2]], 0, 0, 0,   0}, {D[qq5, t][[3]], 0, 0, 0, 0}, {D[qq5, t][[4]], 0, 0, 0,    0}, {D[qq5, t][[5]], 0, 0, 0, 0}};  Vali5 = ConjugateTranspose[Ali5];  Kazi5 = Ali5.Vali5;   m1 = Kazi1 + Kazi2 + Kazi3 + Kazi4 + Kazi5;   sol1 = NDSolve[{D[c[t], t] == (m1).c[t],  c[0] == {1, 0, 0, 0, 0}}, c, {t, 0, 2 tf}];   ans = Evaluate[c[t] /. sol1[[1]]][[5]];  ans1 = Abs[ans]^2;  Plot[ans1, {t, 0, 2 tf}, Frame -> True]  

Hi friends, I need to calculate matrix m1 according to following algorithm. Then, I have to put it in the differential equation. However, matrix m1 is complex and therefore the differential equation does not work.
How can I correct this code to get an answer?

## Are the following statements True or False? Briefly explain your answer

a. Best-first search is a special case of Uniform Cost Search.
b. A heuristic that always evaluates to h(s)=1 for non-goal search node s is always admissible (given that cost value for each node is positive integer)
c. Hill-climbing can be called Greedy Global Search.
d. Local Search uses less memory than Global Search.

Thank you for helping me <3

## How to answer the following queries on a tree?

Given a tree of "N" nodes(each node has been assigned a value A[i],node-"1" is the root of the tree), and a constant "K" , we have Q queries of the following type : [w]

(which means find the lowest valued node in the sub-tree of [w] , only considering those nodes in the sub-tree of [w] which have a depth less than equal to K) .

Example :

Value of nodes of tree :

A[1] = 10

A[2] = 20

A[3] = 30

A[4] = 40

A[5] = 50

A[6] = 60

Edges of tree : [1-2],

[2-3],

[3-4],

[4-5],

[4-6].

K=2.

Query-1 : [w]=1 . All nodes in subtree of [w] : (1,2,3,4,5,6) , now, all nodes in sub-tree of [w] having depth less than equal to K : (1,2) . Hence , minimum(A[1],A[2])=min(10,20)=10 is the answer .

Query-2 : [w]=4 . All nodes in subtree of [w] : (4,5,6) , now, all nodes in sub-tree of [w] having depth less than equal to K : (4,5,6). Hence , minimum(A[4],A[5],A[6]) = min(40,50,60)=40 is the answer .

## Why doesn’t Mathematica provide an answer while Wolfram|Alpha does, concerning a series convergence?

Among other series I’ve been working on, I was asked to find whether $$\sum_n 1-\cos(\frac{\pi}{n})$$ converged, and Mathematica’s output to SumConvergence[1 - Cos[Pi/n], n] simply was repeating the input, without further information. Wolfram|Alpha, though, at least told me which test were or not conclusive.

I’m new to Mathematica, and even though I’ve looked both on Google and into Wolfram’s documentation, I haven’t found information that could help me figure out how to get, from Mathematica, the conditions for the convergence of a series involving something else than powers of a variable.

I would appreciate if you could give me some clues on the typical procedure to make Mathematica correctly evaluate the convergence of a series, or/and to return the conditions for convergence. Thank you in advance.

## What is the 2’s complement answer of 16.5?

According to this post it is saying Two’s complement is only for integers, but in Wolframalpha is is saying the Two’s complement of 16.5 is 0010000.1, how?

## Given two arrays A and B, how do I answer queries asking the qth minimum sum of A[i]+B[j]?

I am given two arrays A and B of same size K (K<=20000). There can be upto 500 queries (offline), each asking the qth minimum sum a+b such that a belongs to A and b belongs to B (q<=10000). How do I answer these queries efficiently?
One way would be to iterate over all pairs but that is too slow for me.