What can modify the area or shape of a Wall of X spell?

Summarizing the question into parts here. I am looking for abilities that do one of the following regarding walls.

  1. Increasing the size of the wall
  2. Changing the shape of a wall
  3. Allow for the moving of a wall

The area of a wall is usually determined by Caster level. Aside from increasing the caster level, is there a way to increase the area of the wall?

Some walls have a distinct shape they need to be formed in while others have the shape-change ability. Is there a way to give these walls the shape-change ability or to add another shape the wall can form into?

Is there anything that could let me move a wall after it’s created? Such as having a Wall of Stone slide along the ground towards a target or to have a Wall of Fire (ring shaped) close in around something?


I can only use first party stuff but the ability can come from any where. Feats, magic item, class feature, etc. are all fair game.

Also does not need to be a Wall of X spell. Spells like Rampart or Forcecage that create a semi-permanent area that restricts or confines movement work as well.


For background I’m making a “Wizard of the Walls” type character. The Wizard’s primary form of combat utilizes walls to corner enemies and forcing them into DoT spells like Flaming Sphere. As such, he scorns the use of any Temporary magic that exists for only the moment it’s cast, such as fireball. So I’m searching for ways to add versatility to the walls he casts.

Connecting older network to existing local area network

I’m attempting to connect two networks right now. The first is a peer to peer containing two systems, one running Windows XP and the other is a CNC router running IBM’s OS/2 Warp. This is an older network, I currently need the Windows XP to be able to view the CNC’s file server and put operations on the CNC router. I have a second network consisting of 4 Windows 10 computers and a few other systems such as a printer. My goal is to remove the Windows XP computer for various reasons and have the Windows 10 computers connect to the CNC router.

I’ve tried connecting all of the systems to the same network through ethernet cables, the Windows XP computer can successfully ping the Windows 10 computers however, the Windows XP computer and CNC router do not show up on the network.

Tangent line of a function in 1st quadrant forms a triangle. Find the Area.

So, i have this particular question, that is Calculus based. Here is the question below:

Consider graph of f(x) = exp(-x), for x>= 0 . The tangent line to the graph of f(x) at x = a, and intersects the x-axis at point A, and the y-axis at point B. Determine the area of triangle AOB in terms of a.

Hence the coordinate on the x-axis is (A,0) and coordinate on the y-axis is (0,B).

I did some work on this. The slope of the tangent line would be : m = -exp(-a) So my equation of the tangent line would be : y = [-exp(-a)]x + B, next i plug in the point : (A,0) Then get the relation B = A*exp(-a), therefore the full equation of the tangent line is: y = -exp(-a)[x-A]

Now the area is of a right triangle with vertices AOB, that area is : Area = AB/2. Plugging in the relation of B = Aexp(-a). Then Area = [(A^2)*exp(-a)]/2

BUT my formula depends on the x-axis coordinate A. SO not sure if this A can be replace with it being related to ‘a’, the point of tangent.

Hope some one can give some input on this.

Look for a clever geometric approach to solve a problem with area.


In the acute $ \triangle ABC$ , the position of each point is as shown, $ F$ is the midpoint of $ BD$ , $ G$ is the midpoint of $ CE$ , $ F$ is not on $ CE$ , and $ G$ is not on $ BD$ . It is known that $ S_{\triangle AFG} = 1$ , and the area of ​​the quadrilateral $ BCDE$ is obtained? enter image description here

An imprecise answer: Considering $ D$ , $ E$ and $ A$ coincide, it is easy to know that the area of ​​the quadrilateral $ BCDE$ is $ 4$ .

Or:Let $ \overrightarrow{AB}=\vec{a}, \overrightarrow{AC}= \vec{b}, \overrightarrow{AE}=\lambda_1 \vec{a}, \overrightarrow{AD}=\lambda_2 \vec{b}, (0 < \lambda_1, \lambda_2<1)$ , then \begin{aligned} S_{\triangle ABC} &= \frac12|\vec{a}\times\vec{b}| \ S_{\triangle AED} &=\frac12 \lambda_1 \lambda_2|\vec{a} \times \vec{b}| \ S_{BCDE} &=S_{\Delta A B C}-S_{\Delta A E D} \ &=\frac{1}{2}\left(1-\lambda_{1} \lambda_{2}\right)|\vec{a} \times \vec{b}| \end{aligned} $ \because$ $ $ \overrightarrow{AF}=\frac{\vec{a}+\lambda \vec{b}}{2} \quad \overrightarrow{A G}=\frac{\lambda_{1} \vec{a}+\vec{b}}{2}$ $

$ \therefore$

\begin{aligned} S_{\Delta A F G} &=\frac{1}{2}\left|\overrightarrow{A F} \times \overrightarrow{A G}\right| \ &=\frac{1}{2}\left|\left(\vec{a}+\lambda_{2} \vec{b}\right) \times\left(\vec{a}_{1} \vec{a}+\vec{b}\right)\right| \ &=\frac{1}{8}\left(1-\lambda_{1} \lambda_{2}\right)|\vec{a} \times \vec{b}| \end{aligned}

$ \therefore$ $ $ \frac{S_{\triangle AFG}}{S_{BCDE}}=\frac{1}{4} \Longrightarrow S_{BCDE}=4$ $

Now, I need a purely geometric approach to solve this problem, but I have no clue. Could anyone help me? Thanks a lot.

How to properly clean my ventilation area on my MacBook Pro

So I moved to a tropical country and have a real problem with mosquitos and alikeenter image description here. They house themselves (dying) in the ventilation area and i regularly clean it up with a cotton swab, but the space is so small that the wholes that connect to the insides stay dirty and i’m worried i’ll have problems, also i like to have my things neat.

What would be the best way to clean this part of my computer, without pushing the mosquitos and the squished entrails deeper into the vents?

Are there any utilities out there that allow you to manually define available screen area?

I have a spare 27 inch monitor that I’d like to use in vertical mode as a side monitor, but it’s way too tall – are there any tools out there that allow you to manually define the effective usable area of the display (as if the screen was actually a different size)?

I’m guessing this would have to be done by the GPU, if it’s even possible?

Here’s a screenshot of what I’m after:

When Antilife Shell is cast, does it push out creatures within its area? If not, how does it work?

Antilife Shell reads:

A shimmering barrier extends out from you in a 10-foot radius and moves with you, remaining centered on you and hedging out creatures other than undead and constructs.

So creatures outside that range can’t approach you, which makes sense. But what about the creatures already inside that radius? If the casting druid is under attack by a humanoid within 5 feet of them, is that humanoid pushed back? Or, as the second parts of the spell says, would that count as “forcing them through the barrier?

If you move so that an affected creature is forced to pass through the barrier, the spell ends.

If you cast it near a creature, are they pushed away from you, or does the spell end? What about if you cast it in a field? Does the grass stop it? Would microbes in a dungeon?

It seems like the spell could be either very powerful—create a dome where there is absolutely no life—or immediately gimp itself.