How to get total amount of reviews belongs to one category? [Magento 1.9]

I am trying to generate SEO rich data in magento category page or listing page. I just dont understand how can i get total amount of reviews that category got. I dont want to slow down the category page.

Is it possible to get that by directly execution sql command?

Please help me 🙁

This code belongs to Equalization with Histogram

My Code brings up this error that “module ‘scipy.misc’ has no attribute ‘fromimage’ “. I have been working on this installed all the packages, still I am not getting any positive result.

One Drive belongs to BIng??

DOes one drive belongs to Bing..
If yes, I would like to share my experiences of One Drive with you here..and an Issue I faced with them after 18-19 years of trust .. what they did with me.?

If alghorithm solves NP problem, for what f(n) can we claim that R belongs to TIME(f(n))?

This is my problem:

Suppose that for the problem R belongs to NP the algorithm of solution check M(x,y) runs in time O(n^3) and uses additional information y, which is long ≤5 log n bits. For what f(n) can we claim that R belongs to TIME(f(n))?

I have no idea how can I know what must to be f(n) that R belongs to TIME(f(n)). Every suggestions are very welcome!

Excel : Summation of data which belongs to certain id

This is my first post in stack exchange. please bear with me and I accept any advice for questioning ethic.

It is easier to illustrate the problem based on the following example:

I have 2 sheets : mapping and data.

1. This Mapping sheet contains a mapping table between a country name and the corresponding ID

2. This table (from Data sheet) contains the country name with the corresponding GDP

The objective is to create a summary table which maps the group id with the SUM of GDP in a seperate sheet

I tried to use the SUM IFS formula as recommended here. They propose the following formula based on their own example.

=SUM(SUMIFS(sum_range,criteria_range,{“blue,”red”}))

However, the challenge arises due to 2 reasons:

1. I cannot list down the ID in an array form as I have many ID variations. Also, the actual ID consists of both numbers and alphabets.
2. I must follow a guideline not to merge the tables into a single sheet.

Thank you in advance!

Could we always find a curve on the manifold whose tangent vector always belongs to a linear subspace?

Suppose we have a smooth manifold $$M$$ and the tangent space of every point $$x \in M$$ has non-empty intersection with a given linear subspace. Could we find a curve on $$M$$ such that the tangent vector of point on thus curve always belongs to this linear subspace?

$$\textbf{My attempt:}$$ If the dimension for the linear subspace is one or two, I think I can find the curve. But I don’t know if the dimension is bigger than two?

I will appreciate for any useful answers and comments

If $f$ belongs to $M^{+}$ and $c \ge 0$ then $cf$ belongs to $M^{+}$ and $\int cf = c\int f$

If $$f$$ belongs to $$M^{+}$$ and $$c \ge 0$$ then $$cf$$ belongs to $$M^{+}$$ and $$\int cf = c\int f$$.

I need to proove that, using the following observation:

if $$f\in M^{+}$$ and $$c>0$$, then the mapping $$\varphi \rightarrow \psi = c\varphi$$ is a one-toone mapping between simple function $$\varphi \in M^{+}$$ with $$\varphi \le f$$ and simple functions $$\varphi$$ in $$M^{+}$$ with $$\psi \le cf$$.

I know that this question is already answer here:One-to-one mapping of simple functions $\phi \to \psi = c\,\phi$ implies $\int cf\,d\mu = c \int f\,d\mu$ ?

But I can’t follow the verbal explanation.

My original idea was to proove $$c \int f \le \int cf \le c\int f$$ But I can’t… some idea?

Is the language { | p and n are natural numbers and there’s no prime number in [p,p+n]} belongs to NP class?

I was wondering if the following language belongs to NP class and if its complimentary belongs to NP class:

\begin{align} C=\left\{\langle p,n\rangle\mid\right.&\ \left. p \text{ and n are natural numbers}\right.\ &\left.\text{ and there’s no prime number in the range}\left[p,p+n\right]\right\} \end{align}

I am not sure, but here’s what I think: for each word $$\langle p,n\rangle \in C$$ we know that the word belongs to C because there exists a primal certificate – an nontrivial divisor to any of the numbers between $$[p,p+n]$$, though I am not really sure it is in NP.

regarding the complement: I think it is in NP because the compliment compositeness can be decided by guessing a factor nondeterministically. But again I am not so sure about it and I don’t know how to correctly prove and show it.

Would really appreciate your input on that as I am quite unsure and also checked textbooks and internet (and this site) about it.

Where f(n) = n! belongs to? P, co-P, NPComplete or NPHard? [duplicate]

This question already has an answer here:

• What is the definition of $P$ , $NP$ , $NP$ -complete and $NP$ -hard? 6 answers
• What is the difference between an algorithm, a language and a problem? 1 answer

Where f(n) = n! belongs to? P, co-P, NPComplete or NPHard?