i need help with the hydra command

Can anyone help me regarding this command hydra -s 80 -l admin -P /root/Desktop/wl/cctvpass.txt -e ns -t 16 192.168.146.49 http-post-form Hydra v9.0 (c) 2019 by van Hauser/THC – Please do not use in military or secret service organizations, or for illegal purposes. After I executed the command this is what came out Hydra (https://github.com/vanhauser-thc/thc-hydra) starting at 2020-09-11 15:58:42 [WARNING] You must supply the web page as an additional option or via -m, default path set to / [ERROR] the variables argument needs at least the strings ^USER^, ^PASS^, ^USER64^ or ^PASS64^: (null) I start at hydra and try to learn

Remote command using Sophos Management

in a recent analysis of a ransomware attack, where BitLocker was used to encrypt the disk, I found that the company was using Sophos.

In the folder C:577-Sophos\AutoUpdate\data\warehouse I found some files that contain executable code and activate BitLocker, using command like the following from disk F: to Z:

manage-bde -on F: -rp 599368-358941-467368-368093-397672-261921-132506-522577 -sk C:\ -s

I’m not really into Sophos management and administration, but I read that the folder warehous can be use as cache for the update installations.

Are these files false positive? Or the malicious actors could use Sophos to spread malicious commands?

Why is Read(Q) timestamp is not checked when a transaction issues a command reading Q?

Consider a concurrent schedule of two transactions $ T_1,T_2$ :

$ R_x(Q): T_x$ Reads $ Q$

$ W_x(Q): T_x$ Writes $ Q$

$ S:R_2(A),R_1(A),W_1(A),W_2(A)$ , this schedule is not conflict serializable.However, if we follow timestamping protocol, where $ TS(T_1)<TS(T_2)$ S is allowed because $ T_1$ can read a variable after $ T_2$ has read it, which is not conflict equivalent to schedule $ T_1 T_2$ and is contradictory to the fact that timestamping protocol gives a conflict serializable schedule. What am I missing here?

How to make multiple right joins in one single command for different child tables?

On the followin image you see 3 tables: A, B , C. A: Is the table that holds the foreign keys from B and C

enter image description here

enter image description here

If I do a right join between A and B on that foreign key, it works, meaning I get the data from column fooB. Same between A and C with fooC.

But If I put both right joins under the same command it fails with null

+-------------+---------------+ | fooB        | fooC          | +-------------+---------------+ | NULL        | abc           | | NULL        | xyz           | 

*This is slightly different as the image with the commands posted below, as this comes straight from the real deployment, however cmds below still show that both columns do not show up.

I’ve tried mixin up left joins, right joins , outer joins all with same result. I have googled about this, but the way my question is formulated is awkard and the hits I get return the traditional right joins for just one table.

How do I get this to work in one command? CMDS Below:

enter image description here

Same commands as above but in text, as comments are asking for text rather than images:

MariaDB [joinPOC]> select fooB from tableA right join tableB on tableB_idtableB=tableB.idtableB; +------+ | fooB | +------+ | b1   | | b2   | | b3   | +------+ 3 rows in set (0.001 sec)  MariaDB [joinPOC]> select fooC from tableA right join tableC on tableC_idtableC=tableC.idtableC; +------+ | fooC | +------+ | c1   | | c2   | | c3   | +------+ 3 rows in set (0.001 sec)  MariaDB [joinPOC]> select fooB from tableA right join tableB on tableB_idtableB=tableB.idtableB right join tableC on tableC_idtableC=tableC.idtableC; +------+ | fooB | +------+ | b1   | | b2   | | b3   | +------+ 

–HERE IS THE ENTIRE SCRIPT–

-- MySQL Workbench Forward Engineering  SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='ONLY_FULL_GROUP_BY,STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_ENGINE_SUBSTITUTION';  -- ----------------------------------------------------- -- Schema joinPOC -- ----------------------------------------------------- DROP SCHEMA IF EXISTS `joinPOC` ;  -- ----------------------------------------------------- -- Schema joinPOC -- ----------------------------------------------------- CREATE SCHEMA IF NOT EXISTS `joinPOC` ; USE `joinPOC` ;  -- ----------------------------------------------------- -- Table `joinPOC`.`tableB` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `joinPOC`.`tableB` (   `idtableB` INT NOT NULL,   `fooB` VARCHAR(10) NOT NULL,   PRIMARY KEY (`idtableB`)) ENGINE = InnoDB;   -- ----------------------------------------------------- -- Table `joinPOC`.`tableC` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `joinPOC`.`tableC` (   `idtableC` INT NOT NULL,   `fooC` VARCHAR(10) NOT NULL,   PRIMARY KEY (`idtableC`)) ENGINE = InnoDB;   -- ----------------------------------------------------- -- Table `joinPOC`.`tableA` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `joinPOC`.`tableA` (   `idtableA` INT NOT NULL,   `fooA` VARCHAR(10) NOT NULL,   `tableB_idtableB` INT NOT NULL,   `tableC_idtableC` INT NOT NULL,   PRIMARY KEY (`idtableA`),   INDEX `fk_tableA_tableB_idx` (`tableB_idtableB` ASC),   INDEX `fk_tableA_tableC1_idx` (`tableC_idtableC` ASC),   CONSTRAINT `fk_tableA_tableB`     FOREIGN KEY (`tableB_idtableB`)     REFERENCES `joinPOC`.`tableB` (`idtableB`)     ON DELETE NO ACTION     ON UPDATE NO ACTION,   CONSTRAINT `fk_tableA_tableC1`     FOREIGN KEY (`tableC_idtableC`)     REFERENCES `joinPOC`.`tableC` (`idtableC`)     ON DELETE NO ACTION     ON UPDATE NO ACTION) ENGINE = InnoDB;   SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS;  -- ----------------------------------------------------- -- Data for table `joinPOC`.`tableB` -- ----------------------------------------------------- START TRANSACTION; USE `joinPOC`; INSERT INTO `joinPOC`.`tableB` (`idtableB`, `fooB`) VALUES (1, 'b1'); INSERT INTO `joinPOC`.`tableB` (`idtableB`, `fooB`) VALUES (2, 'b2'); INSERT INTO `joinPOC`.`tableB` (`idtableB`, `fooB`) VALUES (3, 'b3');  COMMIT;   -- ----------------------------------------------------- -- Data for table `joinPOC`.`tableC` -- ----------------------------------------------------- START TRANSACTION; USE `joinPOC`; INSERT INTO `joinPOC`.`tableC` (`idtableC`, `fooC`) VALUES (1, 'c1'); INSERT INTO `joinPOC`.`tableC` (`idtableC`, `fooC`) VALUES (2, 'c2'); INSERT INTO `joinPOC`.`tableC` (`idtableC`, `fooC`) VALUES (3, 'c3');  COMMIT;   -- ----------------------------------------------------- -- Data for table `joinPOC`.`tableA` -- ----------------------------------------------------- START TRANSACTION; USE `joinPOC`; INSERT INTO `joinPOC`.`tableA` (`idtableA`, `fooA`, `tableB_idtableB`, `tableC_idtableC`) VALUES (1, 'a1', 1, 1); INSERT INTO `joinPOC`.`tableA` (`idtableA`, `fooA`, `tableB_idtableB`, `tableC_idtableC`) VALUES (2, 'a2', 2, 2); INSERT INTO `joinPOC`.`tableA` (`idtableA`, `fooA`, `tableB_idtableB`, `tableC_idtableC`) VALUES (3, 'a3', 3, 3);  COMMIT; 

Desired output in a single command:

+-------------+---------------+ | fooB        | fooC          | +-------------+---------------+ | b1          | c1            | | b2          | c2            | 

How can I hide a flag from `strings` command

I want to create RE CTF, that the user needs to discover which string he need to write in order to execute a function that will print the flag, but, with a simple strings command in shell, we can discover the flag in the printf function. So, how can we make this not to happen?

#include <stdio.h>  void print_flag() {     printf("secret_string discovered. flag: {eAsy_p3asy}"); }  int main() {     int c;     c = getchar();     while (c != 'secret_string') {         putchar(c);         c = getchar();     }     print_flag();     return 0; } 

strings output: I include only the flag. I don’t want the flag to be visible like this, it makes no sense.

secret_string discovered. flag: {eAsy_p3asy} 

Can a Polymorphed creature still command a Dancing Sword?

If a creature has been Polymorphed into a beast, can it still use an already summoned Dancing Sword to attack?

Polymorph says:

The target’s game statistics, including mental ability scores, are replaced by the statistics of the chosen beast. It retains its alignment and personality.

The creature is limited in the actions it can perform by the nature of its new form, and it can’t speak, cast spells, or take any other action that requires hands or speech.

The target’s gear melds into the new form. The creature can’t activate, use, wield, or otherwise benefit from any of its equipment.

Dancing Sword says:

While the sword hovers, you can use a bonus action to cause it to fly up to 30 feet to another spot within 30 feet of you. As part of the same bonus action, you can cause the sword to attack one creature within 5 feet of it.

Calculating percentiles of a FROM command

I have a query which generates a table of trials and values from a database (example pic below)

SELECT * FROM [ReMetrica].[ReMetrica_Result].[GetTrialValuesAsDouble] ('BD5E92F3-3A3B-43B4-BC22-409F34CE5980', 'Total', 'Net Loss', 1) 

which is an expression we’ve been given with this bit of software.

enter image description here

I can calculate the mean of all these trials by using:

SELECT avg(Value) FROM [ReMetrica].[ReMetrica_Result].[GetTrialValuesAsDouble] ('BD5E92F3-3A3B-43B4-BC22-409F34CE5980', 'Total', 'Net Loss', 1) 

However I’m trying to extend this to calculating percentiles as well with

SELECT percentile_cont(Value) OVER [ReMetrica].[ReMetrica_Result].[GetTrialValuesAsDouble] ('BD5E92F3-3A3B-43B4-BC22-409F34CE5980', 'Total', 'Net Loss', 1) 

which doesn’t work due to an ‘incorrect’ syntax after OVER. Could someone help me with where I’m going wrong?