What degree of immortality has metahumanity achieved in the Shadowrun canon?

Considering that today’s (transhumanist) science is actively looking for ways to prolong human life and perhaps to even achieve a kind of immortality in the long run, it seems logical to suppose that with the passing of decades (turbulent as they are), and the aid of supernatural entities and magic, scientific longevity projects have made serious progress in the world of Shadowrun.

My question is:

What degree of immortality has metahumanity achieved in the Shadowrun canon?

How long can the average, advanced citizen (not subject to various extreme risks) expect to live? Is there cheap gene therapy, nanotech cleanup, magical revitalization and so on available for the middle-class masses, be they any subspecies?

If not, what are the major factors that explain, again in the canon, why longevity has not made progress in a world where the adventurous rich can become actual superheroes thanks to bioware, cyberware, and whateverelseware?

I’d primarily be interested in the current canon (SR5 & Anarchy), but if the topic was addressed (only) in earlier editions (and then retconned), that will do as well. 🙂

What is the minimal degree $d$ required for a B tree with $44*10^6 $ keys so that it’s height is less than or equal to $5$

What is the minimal degree $ d$ required so a B – tree with $ 44*10^6$ keys will have a height $ h$ , such that $ h\leq 5$

My attempt was to build the tallest tree possible with minimum degree $ d$ and $ n = 44,000,000$ keys and then solve for $ d$ . That would mean any other tree with a minimal degree $ d’$ such that $ d’\geq d$ and $ n$ keys will be shorter than the one I built:

at depth 0 , we have the root and that’s $ 1$ node

at depth 1, we got exactly $ 2$ nodes

at depth 2, since we’re going for the tallest tree each node will have a minimal number of keys so $ d-1$ keys each, that means $ d$ children each so a total of $ 2d$ nodes.

at depth 3, following the same reasoning , $ 2d^2$ nodes.

at depth $ h$ , there are $ 2d^{h-1}$ nodes

total number of keys is :

$ n = 1+ (d-1)\sum_{k=0}^{h-1} {2d^k} = 1 + (d-1) \frac{2(d^h-1)}{d-1} = 2d^h-1 = 44*10^6 $


$ 2d^5-1=44,000,000 $

$ d= 29.4 $

$ d\geq 30$

is that even correct ?

Why is the distribution of the clustering coefficient of a random network independent of degree?

I was reading about clustering coefficient distribution, and it seems that it is independent of node degree for the case of random networks. I’m wondering why this is the case conceptually.

I do understand that the degree distribution in the case of a random network shows a Poisson behavior, but don’t understand why the clustering coefficient shows no change with degree.

What skills are needed for Web Developer without a college degree? [on hold]

I am a Computer Science major in his freshman year, and I was wanting to know what specific web development skills and languages I should learn to get a job in web development, and what employers are looking for. I work in the dental prosthetics business right now, and am trying to get into a job that is closer to my desired career, software engineering/developing.

Bounds on chromatic number when maximum degree is large

For a regular graph with $ n$ vertices and maximum degree $ \Delta$ , it is easy to see that the chromatic number, $ \chi\le\frac{n}{2}$ if $ \frac{n}{2}\le\Delta\lt n-1$ (since a regular graph on $ n$ vertices with maximum degree $ n-2$ is the complete graph with a one factor removed, which will have each vertex non adjacent to a unique other vertex, which could be given the same color, using the handshaking lemma we get that chromatic number of such a graph is $ \frac{n}{2}$ )

How could this fact be applied to bound the chromatic number of any non-regular graph with large maximum degree. Does this fact have a well known name, like Reed’s theorem, or Brooks’ theorem? Thanks beforehand.

Show that a graph has vertices of all even degrees iff its biconnnected components have all even degree vertices

The biconnected components here are all maximal biconnected components.

When I tried solving the problem in the first direction (if the degrees of all the vertices in the biconnected component were even then the degrees of all the vertices in the graph were even), I ran into the problem of that if the degree of every vertex is even, I wouldn’t be able to connect components to them since then the degree of that vertex that connects the component would be odd.

When I went the other direction ( proving that if the degrees of all the vertices in a graph were even, then the degrees of all the vertices in the maximal biconnected subgraphs are all even), I had a similar issue, that if I find a cut edge and remove it from the biconnected components, then the degrees of those vertices incident to the cut edge now become odd if they were originally even.

I’m not sure what to really do at this point, am I missing something?

Does a degree earned in france get me a job in england

I, a 17 year old boy , plan on following my dream of becoming a computer engineer , currently i can only go to university in france , but i really want to live in england . so will a degree i earned in france where everything is taught in french still get me a job in England ? Does the language you were taught with make a difference?Please excuse my poor grammar , i am working on becoming better