Where can I find lens mounts for small 2 mm diameter lenses?

I need a lens mount for one of my projects. I have a CCD chip, a single lens (2 mm diameter), and I know the mechanical position and tolerances. I would like to find a lens mount for that lens or see whether I can take advantage of some existing small lens mounts, like the Raspbery Pi camera module lens mount. Here are my questions:

What type of lens mount is used on the Raspbery Pi camera module? It seems that the Infenion Tof camera uses the same lens mount.

Which company produces these lens mounts and from which vendor can one buy these small or similar lens mounts (like for mobile phones or other compact devices) that attach to a PCB?

The smallest lens mounts I found was an S Mount M12x0.5 type. For test purposes I bought a couple of female S type lens holder for webcams and then screwed in some of my small S Type lenses. Mechanical play here was too big. I had expected a very tight fit since these are opto-mechanical components, but the lens could still move even when almost fully screwed in.

If $(N,\|.\|)$ is a non trivial vector space with norm, then the diameter of the unit sphere is $\ge2$

It is easy to see that $ \delta(B_1(0))\le 2$ because $ $ \|x-y\|\le\|x\|+\|-y\|=\|x\|+|-1|\|y\|=\|x\|+\|y\|<1+1=2$ $ so $ \sup\{\|x-y\|:x,y\in B_1(0)\}\le 2$

But to show that $ \delta(B_1(0))\ge 2$ we chose $ a\in B_1(0)\backslash\{0\}$ and $ s\in[0,1)$ and observe that $ \|s\frac{a}{\|a\|}\|=s$ $ \implies s\frac{a}{\|a\|},-s\frac{a}{\|a\|}\in B_1(0)$ and $ \|s\frac{a}{\|a\|}-(-s\frac{a}{\|a\|})\|=2s$

But why does that imply that $ \delta(B_1(0))\ge2s$ ?

This is how I think I understand it: the diameter of $ B_1(0)$ is greater than that of $ B_s(0)$ for all $ s\in[0,1)$ because we it contains it. And the diameter of $ B_s(0)$ is $ 2s$ for each $ s$ , which is true because there exists a sequence $ (\epsilon_n\frac{a}{\|a\|},-\epsilon_n\frac{a}{\|a\|})$ of pairs of points, with $ 0\le\epsilon_n<s~\forall n$ and $ \lim\limits_{n\rightarrow\infty}\epsilon_n=s$ such that it is always contained in $ B_s(0)$ and $ \lim\limits_{n\rightarrow\infty}d(\epsilon_n\frac{a}{\|a\|},-\epsilon_n\frac{a}{\|a\|})=2s$

I’m not sure if I got it right…

What is the relationship between lens diameter and exposure?

All of the online calculators for exposure, I have seen, factor in time, film speed, and appature (which is a function of the real appature diameter and the focal length of the lens)

However I would have thought a lens with a larger diameter (with the same focal length and appature) would collect more light and therefore be faster!

Am I just looking at rubbish exposure calculators, or am I missing something?

How is the diameter of a non-circular (effective) aperture actually measured?

An f-number is determined as the ratio of the focal length to the diameter of the entrance pupil. But the actual aperture diaphragm is usually not a perfect circle. Its shape is determined by the number of diaphragm blades and their edge (curved or straight). Depending on those the aperture might be a pentagon, hexagon, octagon… and with straight or curved edges. So how is the diameter actually determined? Is it for example twice the distance between the center and the widest point at an intersection of the blades? Twice the distance between the center and the nearest point on an edge?