http 404 errorThe origin server did not find a current representation for the target resource or is not willing to disclose that one exists

I am new to spring mvc and I have done have everything proper seeing a tutorial.But still I am facing Http 404 error -The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.why is that so?

I’m using IntelliJ IDE and tomcat server to run my code. under WEB-INF/ I have all dispatcher-servlet,jsp,web.xml file.

this is the controller class. I tried both the methods(/hello and /hi) but I’m not able to get successful results. @Controller

public class HelloController {     @RequestMapping("/hello")          public String printHello(ModelMap model) {         model.addAttribute("message", "Hello Spring MVC Framework!");         return "hello";     }     @RequestMapping("/hi")         public ModelAndView hiworld(){         ModelAndView modelAndView=new ModelAndView("hello");         modelAndView.addObject("message","hi bro its ok");         return modelAndView;     } } 

this the dispatcher-servlet.xml.

<bean class = "org.springframework.web.servlet.view.InternalResourceViewResolver">     <property name = "prefix" value = "/WEB-INF/" />     <property name = "suffix" value = ".jsp" /> </bean> 

this is my web.xml file Spring MVC Application

<servlet>     <servlet-name>dispatcher</servlet-name>     <servlet-class>         org.springframework.web.servlet.DispatcherServlet     </servlet-class>     <load-on-startup>1</load-on-startup> </servlet>  <servlet-mapping>     <servlet-name>dispatcher</servlet-name>     <url-pattern>/</url-pattern> </servlet-mapping> 

In hello.jsp file, I am printing the message

<body> <p>$  {message}</p> </body> </html> 

expected result was the successful execution of jsp file. but I’m getting HTTP 404 ERROR-The origin server did not find a current representation for the target resource or is not willing to disclose that one exists.

SharePoint 2013 – A list, survey, discussion board, or document library with the specified title already exists in this Web site

I am getting this error while creating SharePoint site with a specific site template GLOBAL#0 and SRCHCENTERFAST#0. I am able to create site with other templates.

A list, survey, discussion board, or document library with the specified title already exists in this Web site. Please choose another title

New-SPSite -Url "http://sptest.domain.com" -HostHeaderWebApplication "http://spserver:8000/" -Language 1033 -Template "GLOBAL#0" -Name "Data Site" -Description "Data Site" -OwnerEmail "owner@email.com" -OwnerAlias "domain\user" 

Folder from one branch, that’s been added to my .gitignore, exists when I switch to a different branch

I’m working on two branches: branch A and branch B. The contents of each branch are as follows:

**branch A** |-parent |-folder1 |-folder2

**branch B** |-parent |-folder3 |-some_folder |-some_other_stuff |-more_stuff

I have added “some_folder” to .gitignore. New files are created and added to “some_folder” while working on branch B, hence modifying it. Even though it’s supposed to get ignored and git status doesn’t list the folder at all (as it should), when I switch to branch A, folder3 is now listed when I execute ls along with “some_folder”, but when I execute git status it says my working tree is clean. My working tree in branch A now looks like this:

|-parent |-folder1 |-folder2 |-folder3 |-some_folder

Shouldn’t “some_folder” be contained in branch B and not be carried over when switching to my other branch?

How to write this $(\exists (x,y) \in R, y- 3x-2 \wedge y = 1-x^2) $in words?

I am translating the negation of the statement $ (\exists (x,y) \in R, y- 3x-2 \wedge y = 1-x^2) $

$ (\forall (x,y) \in R, y\ne 3x-2 \vee y \ne 1-x^2) $

So far I have, “For every $ (x,y)$ there exists a real number such that $ y\ne 3x-2 $ or $ y \ne 1-x^2$

The reason I am second guessing myself (even if i am correct) is that it doesn’t really make sense to me in the form of a sentence. Am I right? If not, any suggestions?

Given least upper bound $\alpha$ for $\{\ f(x) : x \in [a,b] \ \}$, $\forall \epsilon > 0 \ \exists x$ s.t. $\alpha – f(x) < \epsilon$

I can’t figure out how all of this follows. Taken from Ch.8 of Spivak’s Calculus.

If $ \alpha$ is the least upper bound of $ \{\ f(x) : x \in [a,b] \ \}$ then, $ $ \forall \epsilon > 0 \ \exists x\in [a,b] \ \ \ \ \ \ \ \alpha – f(x) < \epsilon$ $ This, in turn, means that $ $ \frac{1}{\epsilon} < \frac{1}{\alpha – f(x)}$ $

I need create a new module to table exists with another prefix of mam

I need create a new module and this proyect have tables with other prefix, How I ommit this default prefix in my file /Model/ModelTable.php

this is the code inside:

namespace Arkix\Zonas\Model\Resource;  class Zona extends \Magento\Framework\Model\ResourceModel\Db\AbstractDb {      /**      * Construct      *      * @param \Magento\Framework\Model\ResourceModel\Db\Context $  context      * @param string|null $  resourcePrefix      */     public function __construct(         \Magento\Framework\Model\ResourceModel\Db\Context $  context,         $  resourcePrefix = null     ) {         parent::__construct($  context, $  resourcePrefix);          }      /**      * Model Initialization      *      * @return void      */     protected function _construct()     {         $  this->_init('app_places_zones', 'id');     } } 

There exists a linear operator with no proper invariant subspaces

Let $ A$ be a bounded operator on a Hilbert space $ H$ with two invariant subspaces $ M$ and $ N$ s.t. $ N \subset M$ , dim$ (M \cap N^{\perp})> 1$ , and have no invariant subspaces between $ N$ and $ M$ . Then, show that, there exists an operator $ B$ on $ H$ which has no proper invariant subspace.

All I want a hint for constructing $ B$ with the help of $ A$ and given conditions, even a little hint will be appreciated. Thanks in advance.

Prove that f is continuous if and only if there exists a nonempty open subset U ⊆ X such that f(U) C

Let X be a normed space over the complex numbers and let $ T:X\to \mathbb{C}$ be a linear map. Show that $ T$ is a continuous map $ \iff$ there is a subset $ A \subseteq X$ where $ A$ is non-empty and open and $ T(A) \neq \mathbb{C}$ .

Can someone help me with this proof? I know the theory in general but cannot seem to find a way to even begin this problem.