Let’s say a druid is surrounded by enemies. Maybe they’re in a 10ft wide corridor with 2 humanoid enemies on either side. Can they still wildshape into a larger creature? If they can, are the humanoids launched away, or does the druid have to immediately start squeezing?
Most diseases (mundane or magical) and poison deal ability damage upon a failed save after the incubation time.
Once the damage takes place, does the negative effects of a failed save versus disease or poison carry over into an alternate form?
This question is only asking about alternate forms, not wildshape or polymorph.
Is it possible to use a form in a wordpress pwa. I am using the SuperPWA plugin and have a form on the site, the main focus on the site to collect data which is sent to google sheets..works fine. Will I be able capture data if the user is out of connectivity.
Following up on How does Max-HP reduction affect wild-shaped/polymorphed creatures?, which states:
Damage taken in animal form doesn’t affect your original form’s HP unless you’re dropped to 0 HP in animal form and there’s excess damage. Nowhere is it suggested that max-HP reduction would work any differently. Because Wild Shape/Polymorph gives you a new pool of HP, only that pool is affected by the reduction.
A druid gets seduced by a succubus. They kiss while the druid is in bear form – this is not hypothetical as yesterday exactly this had happened. The druid gets lowered Maximum Hit Points because of this forced romance. So according to the linked Q&A, the reduction would only apply to the bear form.
If the druid reverts back to normal, the HP reduction is not active anymore. What if the druid wild shapes another time, back into a bear: does it get a fresh “pool of HP”, or does the Reduced Max HP stay with its bear form until it gets “cured”?
In other words: are shapeshifters actually really resilient against abilities that reduce maximum hit points?
In case it helps to clarify, let’s use these numbers:
- Druid: 45 HP
- Wild Shapes into Brown Bear: 34 HP, but reduced to 10 Maximum HP (after two kisses).
- Druid reverts back to normal: 45 HP
- Wild Shapes back into Brown Bear: 34 HP, or still at 10 HP?
.file 1 “” .section .mdebug.abi32 .previous .nan legacy .module fp=32 .module nooddspreg .abicalls .rdata .align 2 $ LC0: .ascii “Enter number of elements in array0” .align 2 $ LC1: .ascii “%d0” .align 2 $ LC2: .ascii “Enter %d integers20” .align 2 $ LC3: .ascii “Minimum element is present at location %d and its value ” .ascii “is %d.20” .text .align 2 .globl main .set nomips16 .set nomicromips .ent main .type main, @function main: .frame $ fp,448,$ 31 # vars= 416, regs= 2/0, args= 16, gp= 8 .mask 0xc0000000,-4 .fmask 0x00000000,0 .set noreorder .cpload $ 25 .set nomacro addiu $ sp,$ sp,-448 sw $ 31,444($ sp) sw $ fp,440($ sp) move $ fp,$ sp .cprestore 16 movz $ 31,$ 31,$ 0 li $ 2,1 # 0x1 sw $ 2,32($ fp) lw $ 2,%got($ LC0)($ 28) nop addiu $ 4,$ 2,%lo($ LC0) lw $ 2,%call16(puts)($ 28) nop move $ 25,$ 2 .reloc 1f,R_MIPS_JALR,puts 1: jalr $ 25 nop lw $ 28,16($ fp) addiu $ 2,$ fp,436 move $ 5,$ 2 lw $ 2,%got($ LC1)($ 28) nop addiu $ 4,$ 2,%lo($ LC1) lw $ 2,%call16(__isoc99_scanf)($ 28) nop move $ 25,$ 2 .reloc 1f,R_MIPS_JALR,__isoc99_scanf 1: jalr $ 25 nop lw $ 28,16($ fp) lw $ 2,436($ fp) nop move $ 5,$ 2 lw $ 2,%got($ LC2)($ 28) nop addiu $ 4,$ 2,%lo($ LC2) lw $ 2,%call16(printf)($ 28) nop move $ 25,$ 2 .reloc 1f,R_MIPS_JALR,printf 1: jalr $ 25 nop lw $ 28,16($ fp) sw $ 0,28($ fp) b $ L2 nop $ L3: addiu $ 3,$ fp,36 lw $ 2,28($ fp) nop sll $ 2,$ 2,2 addu $ 2,$ 3,$ 2 move $ 5,$ 2 lw $ 2,%got($ LC1)($ 28) nop addiu $ 4,$ 2,%lo($ LC1) lw $ 2,%call16(__isoc99_scanf)($ 28) nop move $ 25,$ 2 .reloc 1f,R_MIPS_JALR,__isoc99_scanf 1: jalr $ 25 nop lw $ 28,16($ fp) lw $ 2,28($ fp) nop addiu $ 2,$ 2,1 sw $ 2,28($ fp) $ L2: lw $ 2,436($ fp) lw $ 3,28($ fp) nop slt $ 2,$ 3,$ 2 bne $ 2,$ 0,$ L3 nop lw $ 2,36($ fp) nop sw $ 2,24($ fp) li $ 2,1 # 0x1 sw $ 2,28($ fp) b $ L4 nop $ L6: lw $ 2,28($ fp) nop sll $ 2,$ 2,2 addiu $ 3,$ fp,24 addu $ 2,$ 3,$ 2 lw $ 3,12($ 2) lw $ 2,24($ fp) nop slt $ 2,$ 3,$ 2 beq $ 2,$ 0,$ L5 nop lw $ 2,28($ fp) nop sll $ 2,$ 2,2 addiu $ 3,$ fp,24 addu $ 2,$ 3,$ 2 lw $ 2,12($ 2) nop sw $ 2,24($ fp) lw $ 2,28($ fp) nop addiu $ 2,$ 2,1 sw $ 2,32($ fp) $ L5: lw $ 2,28($ fp) nop addiu $ 2,$ 2,1 sw $ 2,28($ fp) $ L4: lw $ 2,436($ fp) lw $ 3,28($ fp) nop slt $ 2,$ 3,$ 2 bne $ 2,$ 0,$ L6 nop lw $ 6,24($ fp) lw $ 5,32($ fp) lw $ 2,%got($ LC3)($ 28) nop addiu $ 4,$ 2,%lo($ LC3) lw $ 2,%call16(printf)($ 28) nop move $ 25,$ 2 .reloc 1f,R_MIPS_JALR,printf 1: jalr $ 25 nop lw $ 28,16($ fp) move $ 2,$ 0 move $ sp,$ fp lw $ 31,444($ sp) lw $ fp,440($ sp) addiu $ sp,$ sp,448 j $ 31 nop .set macro .set reorder .end main .size main, .-main .ident “GCC: (Ubuntu 5.4.0-6ubuntu1~16.04.9) 5.4.0 20160609”
The Animal Shapes spell allows the caster to transform “willing” creatures in range into an animal.
The transformation lasts for the Duration for each target, or until the target drops to 0 Hit Points or dies.
Would an affected creature be able to drop this form at will?
On one hand, the spell explicitly states only 2 events can break it (spell naturally ending, creature dropping to 0HP)
However, it could be argued the creature no longer meets the criteria to be transformed since they are no longer willing.
The spell requires concentration which also lends credibility to the idea that the willingness check may be a continuous thing.
The recurrence form of bubble sort is $ T(n)=T(n-1)+ n- 1$
How can I prove by induction that this is $ \Omega(n^2)$ ?
I’m stuck with $ T(n+1) \geq cn^2 + n = n(cn+1)$
I’m a mobile app developer developing an app that gets input from users like mobile number, email id, and user name. I’m a bit confused about how to select the encryption method like Symmetric or Asymmetric and how to transmit the data from the app to the server.
Since I’m developing an app that will get user information like
user name, and
password. The App will share the user name and mobile number for other users to discover that person. In that way how should I encrypt the data (
Mobile number and
username) to store it in the database and how to decrypt it later in the App. I’ll hash the password so no worries in storing the password. The only thing is
- What encryption method should I want to use for this scenario?
- Which algorithm should I choose Symmetric or Asymmetric algorithm?
- How to store the encryption key safe in the app?
I am working on a security testing project, where I have noticed that the form action of a login page takes whatever is fed to URI as a parameter, the respective part of the login page is as follows:
<form action="/admin/login/?param=Whateveryouputhere" method="post" id="login-form">
Actually, you can even omit the “param”, any value after the question mark will still be reflected. the default value for te param is “/next/” btw.
How could an attacker exploit it, especially via XSS? I tried to escape the the quotations but it failed (they are auto-replaced with URL-encodings). Does it mean it is safe?
I have also checked the network tab of the browser, no other relative JS files are loaded except favicon and magnific popup.
Finally, the URL is in the form of site.com/admin/login/?param=value
I studied Artificial intelligence a long time ago and I’ve had no interest in it. I studied Artificial intelligence a long time ago and I’ve had no interest in it. But recently one of my friends asked me to change the following states into predicate form by using a standard form. Can someone help me?
• Marin is married to Sylvia who has a daughter Joy. • Harry is the son of Amos who is married to Joy. • The parent of one’s parent is his/her grandparent.
• If a person is married to another person who has a child then the first person is also a parent of the child.
• If a person is married to another person then the latter person is married to the former.
Change these sentences to predicate form, by using the standard form of logic and the following predicates: parent(X, Y), grandparent(X, Y), and married_to (X, Y).
I know it may look simple for some of you. But I recently went to another field about 2 years ago. Thank you.