Tag: frame

“View frame source” is suddenly an option on every website loaded with Chrome

I’m running Google Chrome Version 83.0.4103.61 (64-bit) on Windows 10, and I’ve suddenly noticed that never mind what website I visit, when I right click “View frame source” is an option.

This strikes me as odd, as that option is usually only available when you’re wanting to view the source code of an iFrame. Whether I click “View frame source” or “View page source” the source code and URL are the same.

But why does Chrome suddenly think that any website I load is being displayed in a frame? Is this cause for concern or am I just being paranoid?

mimic a image frame

When I read a paper, I found a image just like following:

enter image description here

I don’t care about the real curve functions, I only want drawing like it. So I try to coding:

g1 = RegionPlot[y > 3 x^2, {x, 0, 1}, {y, 0, 1}, PlotStyle -> LightBlue, BoundaryStyle -> Directive[Orange]]; g2 = RegionPlot[y > 2 x^2, {x, 0, 1}, {y, 0, 1}, PlotStyle -> LightYellow, BoundaryStyle -> Directive[Red, Dashed], FrameStyle -> Directive[Black, 16]]; Show[g2, g1]

My questions are: 1. How to drawing the black frame like the first image? 2. Mesh option will achieve this grids effect? 3. Mesh->All will affect the BoundaryStyle option?

enter image description here

China Rectange Globulite MDF Photo Frame suppliers

※ Our History
Yiwu LIQU Digital Graphic Co. Ltd, which is the most professional manufacturer of sublimation products in China over 15 years, major in sublimation mugs, plates, heat press machines, MDF boards, rock slates etc.
                 
※ Our Factory
10,000 square meter factory,120 working staffs.80,000pcs blank white mugs and 5,000pcs customized mugs per day
※ Our Product
Sublimation white mug, magic mug, water bottle, rock slate, MDF frame
Product Application
Drink ware, promotional gift
※ Our Certificate
SGS
※ Production Market
North America,South America, Europe
※ Our service
Accept OEM order; provide designs.China Rectange Globulite MDF Photo Frame suppliers
website:http://www.liquprinting.com/
website2:http://www.sub-blanks.com/

Calculating page frame size from the physical address size

This question is in regards to the question below

The physical memory is split into physical pages (aka page frames), which have equal size. We know that the number of page frames in the physical memory equals the number of bytes in a page frame. We also know that physical addresses have 10 bits. How many bytes are in a page frame?

I am struggling with the link between physical addresses and the number of bytes in a page frame

I am correct in thinking the page frame must be the same size as the physical memory. Given that the physical address is 10 bits am I correct in saying

2^10 = 1KB = 1000 Bytes?

Filtrar filas en un Data Frame en R si se cumple condición de una de las variables

Tengo un data frame en el cual se registran datos de atenciones para población en estado de embarazo, pero necesito filtrar los datos de atenciones para las mujeres que únicamente tuvieron partos, como el caso del ID 43631224 o 107165943, se desea identificar sólo las atenciones que incluyeron el diagnóstico PARTO, los códigos para ese diagnóstico están estandarizados.

Gracias por la ayuda

Datos atenciones de Salud mujeres emabarazadas

Global variables and frame stack

The below program will read a positive integer from keyboard and print the binary equivalent. This program is using only one variable.

If global variables are not stored in frame stack, how this is working.

include

int n; void binary(n) { if(n>0) { binary(n/2); printf(“%d”,n%2); } }

void main() { scanf(“%d”,&n); binary(n); }

Exception in thread “main” java.awt.IllegalComponentStateException: The frame is decorated

galera voltei, comecei a estudar AWT fiz um programinha simples que apenas abria uma janela com um fundo verde, mas eu tento criar um evento pra janela do programa fechar e fica dando o erro do título

nome completo do erro:
Exception in thread “main” java.awt.IllegalComponentStateException: The frame is decorated at java.desktop/java.awt.Frame.setOpacity(Frame.java:963) at Ventana.main(Ventana.java:19)

codigo que estou usando:

import java.awt.Frame; import java.awt.event.ActionEvent; import java.awt.Color; import java.awt.event.WindowEvent; import java.awt.event.WindowAdapter;  public class Ventana {      public static void exitForm(WindowEvent evt){         System.exit(0);      }      public static void main(String[] args){         Frame frame = new Frame("Novo video!");         frame.setUndecorated(false);         frame.setSize(600,600);         frame.setLocation(520,250);         frame.setOpacity((float)0.50);         frame.setBackground(new Color(161, 203, 70));         frame.addWindowListener(new WindowAdapter() {             public void windowClosing(WindowEvent evt){                 exitForm(evt);             }          });         frame.show();       }  }

sou bem novato, desculpa se estou fazendo um erro bem “noob”, mas já agradeço pela atenção <3

libgdx, png asset – Different size of animation frame assets – possible to center?

I have code that changes texture in each frame depending on state of player – walking, idle. Problem is that idle texture (from separate png) has slightly different size and due to that it appears not in line with rest of animations seemingly being in slightly different position when returning to idle. Is it possible to position them based on the center of texture instead of left bottom?

batch.draw(determineTexture(), position.x, position.y,             currentFrame.getRegionWidth()/2f, currentFrame.getRegionHeight()/2f,             currentFrame.getRegionWidth(), currentFrame.getRegionHeight(),1f,1f, rotation,false);  TextureRegion determineTexture(){         if(playerState == State.idle)             currentFrame = idleAnimation.getKeyFrame(stateTime, true);         else if (playerState == State.walkingUP || playerState == State.walkingDOWN || playerState == State.walkingRIGHT || playerState == State.walkingLEFT )             currentFrame = walkAnimation.getKeyFrame(stateTime, true);         return currentFrame; }

One png has height of 57 – idle, while 6 columns and one row of walking frames has height of 87 pixels

Calculate minimum and maximum Ethernet (IEEE 802.3) frame size from frame format

enter image description here

According the frame format of Ethernet

Minimum Frame Size should be : $ 7 Byte + 1Byte+6Bytes+6Bytse+2Bytes+46Bytes+4Bytes=72Bytes$

Maximum Frame Size should be : $ 7 Byte + 1Byte+6Bytes+6Bytse+2Bytes+1500Bytes+4Bytes=1526Bytes$

But it is said that the minimum frame size is $ 64Bytes$ while the maximum frame size is $ 1518 Bytes$ .

How the frame sizes are calculated ?