PDO INSERT INTO with SELECT no agrega registros a la base de datos phpmyadmin

La cadena “INSERT INTO admin_history (user_id, username, usernick, userlevel, delete_user_id) SELECT user_id, username, usernick, userlevel, delete_user_id FROM user WHERE (user_id =: user_id)” no escribirá datos en la base de datos.

Si en lugar de: user_id sustituye la identificación existente, el registro funciona.

No escribí el código yo mismo, tomé http://demo.webslesson.info/multiple-checkbox-update-data/ aquí e intenté agregar la capacidad de ver el historial de cambios en el sitio http://yamer7.beget.tech/panel-admin.

include($  _SERVER['DOCUMENT_ROOT'].'/sql_connect.php');  if(isset($  _POST['user_id'])) {     $  new_id = $  _POST['new_id'];     $  user_id = $  _POST['user_id'];     $  username = $  _POST['username'];     $  usernick = $  _POST['usernick'];     $  userlevel = $  _POST['userlevel'];     $  delete_user_id = $  _POST['delete_user_id'];     for($  count = 0; $  count < count($  user_id); $  count++)     {         $  data = array(             ':new_id'   => $  new_id[$  count],             ':user_id'   => $  user_id[$  count],             ':username'  =>  $  username[$  count],             ':usernick'  =>  $  usernick[$  count],             ':userlevel'  =>  $  userlevel[$  count],             ':delete_user_id'  =>  $  delete_user_id[$  count]     );     $  query0 = "INSERT INTO admin_history (user_id, username, usernick, userlevel, delete_user_id) SELECT user_id, username, usernick, userlevel, delete_user_id FROM user WHERE (user_id = :user_id)";     $  statement0 = $  connect->prepare($  query0);     $  statement0->execute($  data);     $  query1 = "UPDATE user SET user_id = :new_id, username = :username, usernick =:usernick, userlevel = :userlevel, delete_user_id = :delete_user_id WHERE (user_id = :user_id)";     $  statement1 = $  connect->prepare($  query1);     $  statement1->execute($  data);     $  query2 = "DELETE FROM user WHERE delete_user_id=1";     $  statement2 = $  connect->prepare($  query2);     $  statement2->execute($  data);     } } 

Escriba cuál es la mejor manera de hacerlo si deseo guardar muestras múltiples durante INSERT INTO para que todos los registros modificados seleccionados en la casilla de verificación se escriban en la base de datos.

insert form em php (Notice: Undefined index:origem)

Estoy realizando um ejercicio de curso, al hacer el formulario para registro me apresenta el error: Notice: Undefined index:. Ya intente de todo hasta escribir todo el codigo de nuevo y sigo com el mismo problema.

<?php   require 'funcs/conexion.php'; var_dump($  _POST);  $  origem = $  _POST['origem'];  $  sql= "INSERT INTO test (origem)  VALUES ($  origem) "; $  resultado= $  mysqli->query($  sql);  if($  resultado){   echo "dados salvo com sucesso"; }else{    echo "erro ao salvar dados"; }  ?> 

Y mi .html desde donde llamo al .php es:

<!DOCTYPE html>   <html lang="en">   <head>     <meta charset="UTF-8">     <title>Document</title>   </head>   <body>     <form action="insertar_test.php" method="post">       <label>origem</label>       <input type="text" name="origem" id="origem">       <button type="submit" class="btn btn-primary" >salvar</button>     </form>   </body> </html> 

How To insert field of type lookup in the SharePoint List

I have a list with name Product Catalog and there are two lookup fields with name Country Preference and Location Preference one date field and multiselect field.

I tested with list name without any space ex:- employee and simple field types and able to insert the data in the list without error. But with the above list name and the field types I am not able to insert the data. Error no. 400 Bad Request is displaying in the browser debugging console.

Might be there is problem in preparation of item as given below.

Can any one help me in correct preparation of item which i have to use it as payload in request.

I wanted to know following things specified inline in the below item variable.

var item = { “__metadata”: { “type”: itemType }, datefield : correct value format, multiselect field : correct value format, correct Country Preferences lookup field name: correct value format, correct Location Preferences lookup field name: correct value format };

Also what should be the name format for the ‘ListName’ in the below url?

url: “http:///_api/web/lists/GetByTitle(‘ListName’)”,

jQuery.ajax({ url: “http:///_api/web/lists/GetByTitle(‘ListName’)”, type: “POST”, data: JSON.stringify(item), headers: { “X-HTTP-Method”:”MERGE”, “accept”: “application/json;odata=verbose”, “content-type”: “application/json;odata=verbose”, “content-length”: , “X-RequestDigest”: $ (“#__REQUESTDIGEST”).val(), “IF-MATCH”: “*” }, success: doSuccess, error: doError });

Thanks & Regards, Gopi

How do I insert “Created by” into a concatenate formula?

To have month view in a SharePoint calendar which displays the value of more than one field.

I would like to combine the Title with the user’s name using calculated column type. But Createdby can’t be used in the formula

Title& ….

Can someone tell me how I can show the values of both title and user name in the month view of a SharePoint ?

Many thanks in advance.

Martine.

error en insert into

me podrian colabora e tratado de que el codigo se ejecute pero no funciona que puedo hacer ya verifique el nombre de la columnas y como las llamo, tambien la conexion, de igual manera el formulario lo que creo que falla es el INSERT INTO pero no en que o que estara fallando oara que el codigo no se ejecute adecuadamente.

$  dbhost = 'localhost';  $  dbuser = 'root';  $  dbpass = 'root';  $  dbtabla ='dbcuentas';  $  dbport = 3306;   $  conx = mysqli_connect("$  dbhost:$  dbport" , $  dbuser , $  dbpass);     $  dbdato = mysqli_select_db( $  conx, $  dbtabla );   $  usuario = $  _POST['usuario'];  $  password = $  _POST['password'];  $  email = $  _POST['email'];  $  cedula = $  _POST['cedula'];  $  movil = $  _POST['telefono'];    $  insert = " INSERT INTO cuenta( usuario, password, email, cedula, movil)  VALUES('$  usuario', '$  password', '$  email', $  cedula, $  movil)";    $  peticion = mysqli_query( $  insert, $  dbdato );  if($  peticion){   echo 'lo lograste porfin'; }  else{   echo 'vamos sigue intentando'; } 

introducir la descripción de la imagen aquí

Como puedo realizar un insert dentro un if

Hola amigos tengo este código en mysql mis 2 variables proveedor…esta variable viene de un stored producre y todo bien Acumulado_1…esta variable es la que declaro para compararla. Lo que yo quiero que me haga el if es que si Acumulado_1 viene null pues que me haga el insert. saludos

SET Acumulado_1 = (SELECT Idproveedor FROM acumuladocomisiones                     WHERE Idproveedor =proveedor); ELSEIF (Acumulado_1 is null) THEN UPDATE acumuladocomisiones SET MontoAcumulado=Total_Prove WHERE Idproveedor=proveedor; 

MySQL import – all rows missing except those in final INSERT of InnoDB tables

This is a very strange bug. I’m using this on a mac:

mysql Ver 15.1 Distrib 10.4.6-MariaDB, for osx10.13 (x86_64)

If I import an SQL dump of a WordPress DB (so not very complicated structure, but some long lines) from the command line, the table structure for all tables appears normal, but lots of content is missing from InnoDB tables.

Specifically, where the INSERTS have been ‘chunked’ into groups of records, only the final group is there. If I use --skip-extended-insert to write a statement for every record, only one record is ever in the InnoDB table.

MyISAM data seems fine.

I’ve tried dropping and recreating the database, could there be some corruption elsewhere?