The Question of the CLRS $ 6.1-7$ exercise reads as:

Show that, with the array representation for sorting an n-element heap, the leaves are the nodes indexed by $ \lfloor n / 2 \rfloor + 1, \lfloor n / 2 \rfloor + 2, \ldots, n⌊n/2⌋+1,⌊n/2⌋+2,…,n$ .

I looked for the solution here: https://walkccc.github.io/CLRS/Chap06/6.1/

The solution was provided like this:

Let’s take the left child of the node indexed by $ \lfloor n / 2 \rfloor + 1.$

\begin{aligned} \text{LEFT}(\lfloor n / 2 \rfloor + 1) & = 2(\lfloor n / 2 \rfloor + 1) \ & > 2(n / 2 – 1) + 2 \ & = n – 2 + 2 \ & = n. \end{aligned}

I can’t understand this statement: $ LEFT(⌊𝑛/2⌋+1) > 2(𝑛/2−1)+2$

Please help me out. Thank you.