Thank you all for your input! It is my belief that if we continue finding things wrong with it, we can eventually find the right! This is an updated proof with conversations I’ve been having all across the web. I do appreciate all constructive input. Let me know what you think. 🙂

The Proof of Everything & Nothing (The Solution to Complexity Theory)

Assume The Set of Everything & Call it {EXPSPACETIME}:

Assume The Empty Set {∅}:

Assume non means negation of:

*The Time Part:*

Assume deterministic time problems {P} is true. This implies non-deterministic time problems {NP} is the negation of {P}. So, {P}=/={NP}. As a result, there is only {P}.

Assume {NP} is true. This implies {P} is the negation of {NP}. As {P} is already assumed true, {P}={NP}.

This creates a paradox where: {P}={NP} & {P}=/={NP}. However, they can’t equal and not equal at the same time. Therefore, they must only be true in different sets. The set {{P}={NP}} & the set {{P}=/={NP}}.

However, there also needs to be another set where the deterministic time paradox is true because both are included in the everything set. Therefore, there are 3 temporal deterministic sets. {{P}={NP}}, but not {{P}=/={NP}}, one where {{P}=/={NP}}, and one where both are true at once {{{P}={NP}},{{P}=/={NP}}} or {EXPTime} for short. The other possibility can’t be true because both {P}={NP} and {P}=/={NP} are false making absolute nothingness, or the set with nothing it {∅}.

*The Space Part:*

Assume deterministic Space problems {Space} is true. This implies non-deterministic {Space} problems {NSpace} is the negation of {Space}. So, {Space}=/={NSpace}. As a result, there is only {Space}.

Assume {NSpace} is true. This implies {Space} is the negation of {NSpace}. As {Space} is already assumed true, {Space}={NSpace}.

This creates a paradox where: {Space}={NSpace} & {Space}=/={NSpace}. However they can’t equal and not equal at the same time. Therefore, they must only be true in different sets. The set {{Space}={NSpace}} & the set {{Space}=/={NSpace}} are separate.

However, there also needs to be another set where the deterministic space paradox is true because both are included in the everything set. Therefore, there are 3 spatial deterministic sets. One where {{Space}={NSpace}}, one where {{Space}=/={NSpace}}, and one where both are true at once or {{{Space}={NSpace}},{{Space}=/={NSpace}}} or {EXPSpace} for short. The other possibility can’t be true because both {Space}={NSpace} and {Space}=/={NSpace} are false making absolute nothingness, or the set with nothing it {∅}.

The *The SpaceTime Part:*

The Everything set {EXPSPACETIME} is the union of the 2 subsets {EXPSpace, EXPTime}

The Everything & Empty Set as the union of Everything Set & Empty Set {{EXPSPACETIME},{∅}} which I would like to call {EXPSPACETIME∅}.

However, the union of the set of everything and the empty set is a set. Which means it is it’s own set of {{EXPSPACETIME∅},∅}, or in other words {EXPSPACETIME∅∅}.

This continues ad infinitum, which means the only thing that exists is the set, which is also everything. Therefore {EXPSPACETIME}={EXPSPACETIME∅,…∅n} where ∅n is any number of ∅.

~Michael Barry “I Got Clap But Im Not A Clapper”