## In what cases is solving Binary Linear Program easy (i.e. **P** complexity)? I’m looking at scheduling problems in particular

In what cases is solving Binary Linear Program easy (i.e. P complexity)?

The reason I’m asking is to understand if I can reformulate a scheduling problem I’m currently working on in such a way to guarantee finding the global optimum within reasonable time, so any advice in that direction is most welcome.

I was under the impression that when solving a scheduling problem, where a variable value of 1 represents that a particular (timeslot x person) pair is part of the schedule, if the result contains non-integers, that means that there exist multiple valid schedules, and the result is a linear combination of such schedules; to obtain a valid integer solution, one simply needs to re-run the algorithm from the current solution, with an additional constraint for one of the real-valued variables equal to either 0 or 1.

Am I mistaken in this understanding? Is there a particular subset of (scheduling) problems where this would be a valid strategy? Any papers / textbook chapter suggestions are most welcome also.

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## memory storage of a program before compiling

Whenever we write code, after compilation the code will be converted to machine language and then stored in the hard disk. But before compiling the code, it is still in the high-level language. How and where the memory is allocated for the code before compiling the code while it is in a high-level language.

I assume, before compiling the code is stored in RAM, but how? because we can only store in machine language in RAM.

If there is any wrong with my question or it is a wrong way of asking, please comment below. It will be helpful

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## My any-dice program times out, when calculating large limit break checks

Someone in chat helped write an anydice program to calculate limit breaks in an RPG I’m developing, but after making some changes, it times out for dicepools > 7.

The system I have in mind, is that if any of the dice you roll is below a threshold, you can bank the sum of all failed rolls for later use, by converting it into a limit break token (currently, at an exchange rate of 1:4). I’m toying with requiring a certain number of successes before you can convert failed, which may or may not be slowing down the program.

``function: sum X:s less than L with at least K successes {   R: 0   S: 0   loop I over X {      if I <= L { R: R + I }      if I > L { S: S + 1 }   }   if S >= K { result: R/4 }   if S < K { result: 0 }  } ``

Is there a more efficient way of running this program? Initially before my tweaks, the same helpful person suggested this as an alternative to the function: `output 3d{1..6, 0:6} named "Alt dice"` but I can’t figure a way of running that, which is probably less likely to time out, and still check for a minimum number of successes.

Here is the code that causes the time out:

``output [sum 1d12 less than 7 with at least 0 successes] named "1 die limit break" output [sum 2d12 less than 7 with at least 1 successes] named "2 die limit break" output [sum 3d12 less than 7 with at least 1 successes] named "3 die limit break" output [sum 4d12 less than 7 with at least 1 successes] named "4 die limit break" output [sum 5d12 less than 7 with at least 1 successes] named "5 die limit break" output [sum 6d12 less than 7 with at least 1 successes] named "6 die limit break" \Times out around here\ output [sum 7d12 less than 7 with at least 1 successes] named "7 die limit break" output [sum 8d12 less than 7 with at least 2 successes] named "7 die limit break" output [sum 9d12 less than 7 with at least 2 successes] named "7 die limit break" output [sum 10d12 less than 7 with at least 2 successes] named "7 die limit break" ``

I found the timeout point by running each line individually.

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## How to prove that the dual linear program of the max-flow linear program indeed is a min-cut linear program?

So the wikipedia page gives the following linear programs for max-flow, and the dual program : While it is quite straight forward to see that the max-flow linear program indeed computes a maximum flow (every feasable solution is a flow, and every flow is a feasable solution), i couldn’t find convincing proof that the dual of the max-flow linear program indeed is the LP of the min-cut problem.

An ‘intuitive’ proof is given on wikipedia, namely : $$d_{uv}$$ is 1 if the edge $$(u,v)$$ is counted in the cut and else $$0$$, $$z_u$$ is $$1$$ if $$u$$ is in the same side than $$s$$ in the cut, and $$0$$ if $$u$$ is in the same side of the cut than $$t$$

But that doesn’t convince me a lot, mainly why should all the variables be integers, while we don’t have integer conditions ?

And in general, do you have a convincing proof that the dual of the max-flow LP indeed is the LP formulation for min-cut ?

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## Problem running C program [closed]

I am using Windows 10 OS. I installed MinGW for compiling C programs. I tried running my program using the gcc command on the Command Prompt. The file compiles and an executable file(.exe) is formed in the same folder as my source file. But when I try running this file, I keep getting the message ‘Access is denied’. Also the .exe file vanishes after this. I do not know what is wrong. Please help me out.

P.S Another time I did the same thing mentioned above and the .exe file ran and I was able to see the output on the Command line. And this time the .exe file did not vanish either.

## Solve a linear program in \$O(m^2)\$

Given $$max(c_1x_1+c_2x_2)$$ s.t $$a_1x_1+b_1x_2\le d_1$$ $$…$$ $$a_mx_1+b_mx_2\le d_m$$ $$x_1,x_2\ge0$$

I need to find an algorithm that solves this in $$O(m^2)$$. I’ve been trying to solve this for quite some time but no luck. Any idea?

## A Netrunner using a stealth program, apply the stealth effect only to his icon or also to all his programs active in the Netmap?

When the netrunner is in a cell of the netmap, and run program "invisibility" for instance, do the other programs launched by netrunner will be invisible as well? Or only the Netrunner "icon" will be invisibile?

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## How to program a situation like the following in mathematics and generalize the process to other configurations?

Distribute the numbers from 1 to 10(view image) so that the sum of each row and each column is the same and a) the maximum possible b) the minimum possible (I put it from 1 to 10 for ease)

I know it is a problem that could work with matrices or lists but I can’t think how to start Posted on Categories cheapest proxies

## How did this Example.name came and hows its used in the following program

class Example {

//static variable salary public static int age;

public static String name = “Gautam”; }

public class Person

{ public static void main(String args[]){

//acess variable without object Example.age=45;

System.out.println(” Name of a person:”+Example.name);

System.out.println(“Age of a person:”+Example.age);

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## Write a program that accepts the radius of a circle in the client side of a program and compute the area and perimeter in the server side program

Write a program that accepts the radius of a circle in the client side of a program and compute the area and perimeter in the server side program and return the values to the client program.

``// Client   import java.io.*; import java.net.*;  public class Client {             public static void main(String[] args) throws IOException{                 Socket s = new Socket("localhost",1234);                 BufferedReader br;                 PrintStream ps;   String str;                System.out.println("Enter Radius  :");                 br=new BufferedReader(new InputStreamReader(System.in));    ps=new PrintStream(s.getOutputStream());                ps.println(br.readLine());    br=new BufferedReader(new InputStreamReader(s.getInputStream()));                str=br.readLine();                System.out.println("Area of the circle is : "+str);                 br.close();                 ps.close();            } } ``
``// Server  import java.io.*; import java.net.*;  class Server {       public static void main(String[] args){           try {           ServerSocket ss = new ServerSocket(1234);                  System.out.println("Waiting for Client Request");                   Socket s=ss.accept();                   BufferedReader br;                   PrintStream ps;                   String str;                   br=new BufferedReader(new InputStreamReader(s.getInputStream()));                   str=br.readLine();                   double r=Double.parseDouble(str);                   double area=3.14*r*r;                   ps=new PrintStream(s.getOutputStream());                   ps.println(String.valueOf(area));                   br.close();                   ps.close();                   s.close();                   ss.close();        }           catch(Exception e)           {                       System.out.println(e);           }  } }  ``

how to add perimeter of a circle

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