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Fit in squares in a dedicated space

A random number between 2 and 100, What I want to do is; create a number of squares(doesn’t have to be, any shape is ok) that will fit accordingly inside the dedicated space for them(let’s say half of the screen, etc).

if the number is 2, create 2 squares that are 1/2 space size big. if the number is 10, create 10 squares 1/10 space size big. maximum squares per rows and columns are 10… Example: enter image description here

How can I achieve something like this, any tutorial or idea?

Reformatting a table to save vertical space

To save vertical space, how can I convert a $ c$ column $ r=kn$ row table to a $ ck$ column $ n$ row table? E.g., a $ 6=3\cdot2$ row $ 3$ column table to a $ 3\cdot3=9$ column $ 2$ row table;

a11 a12 a13 a21 a22 a23 a31 a32 a33 a41 a42 a43 a51 a52 a53 a61 a62 a63 

to

a11 a12 a13 a31 a32 a33 a51 a52 a53 a21 a22 a23 a41 a42 a43 a61 a62 a63 

TIA.

Enumerating points on the integer lattice, within a sphere, sorted by angle, in O(1) space

Inspired by this StackOverflow question: https://stackoverflow.com/questions/63346135

(it was not clearly presented, and got closed)

Let’s say I wanted to enumerate all the 3D points on the integer lattice, within a sphere, in order of the angle between the vector to the point and the up vector (say z).

Could I do this in O(1) space efficiently?

All I can find is:

Remembering last point (init at (0,0,0)). (O(1) memory) while true     init best dot product to 0     going through all 3D points (three nested for's with radius range)         if this point has better dot product but least than last point             keep this point as best     if best dot product is still 0, exit      pick best point as current point (this is where the listing occurs)     update last point to best point 

Not only is this absolutely slow, it also needs the use of integer math for dot product and length so that numerical precision doesn’t mess with symmetrical points and it would also need a tweak to guarantee symmetrical points are listed in a known order.

Is there any good algorithms that would apply here?

what will be space complexity for snippet for(i=1 to n) int x=10;?

The space complexity of the code snippet given below-

int *a=malloc(n*sizeof(int)); int sum=0; for(i=0;i<n;i++) { scanf("%d",&a[i]); for(j=0;j<n;j++) { int x=a[i]; sum=sum+x; } } free(a); 

This is question of a test. I answered it O(n), considering space only for array and constant space for rest of the code. But in the answer they given O(n^2) and there explanation is "The array is of size n and the inner most loop we are declaring a variable x every time the loop is executed, this loop is executed O(n^2) time hence overall space complexity is O(n^2)." Now my doubt is what should be space complexity of

for(i=1;i<=n;i++)    int x=10; 

What i thought is that it should be O(1) because in each iteration variable x gets destroyed. Please someone help me…i searched but found nothing satisfactory.

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How to remove extra white space above text

Hello I am trying to get this text "*SCRC Reading Room is closed for the Fall 2020 Semester" closer to "Bird Library: View Service desk hours" How would I do that given this code.

 <h3 class="hours-h3">Bird Library</h3> <script src="//api3.libcal.com/js/hours_grid.js?002"></script> <div id="s-lc-whw1503"></div> <script> $  (function(){ var week1503 = new $  .LibCalWeeklyGrid( $  ("#s-lc-whw1503"), { iid: 3186, lid: 1503,  weeks: 8 }); }); </script> *SCRC Reading Room is closed for the Fall...
Code (markup):

How to remove extra white space above text

Rotate Object in world space – Raytracing

I’m programming a C raytracing project.

I’ve been wanting to implement object rotations (square, cylinder) for several days but I can’t do it.

For each object, I have its position (x, y, z) in the world space and its 3d normalized orientation vector.

For the moment, I do nothing more than applying once of the three following functions on the 3d normalized orientation vector. I don’t know if I’m doing it right. Rotation doesn’t work well.

For example, I want to rotate my object left with the j key and right with the l key (x_rotation), up with the i key and down with the k key (y_rotation). I’m not sure how to use the z axis.

I’m starting to despair, can you please help me?

I will be very grateful for your help 🙂

t_vec       x_rotation(t_vec vec, float alpha) {     t_vec   res;      res.x = vec.x;     res.y = vec.y * cos(alpha) - vec.z * sin(alpha);     res.z = vec.y * sin(alpha) + vec.z * cos(alpha);     return (res); }  t_vec       y_rotation(t_vec vec, float alpha) {     t_vec   res;      res.x = vec.z * sin(alpha) + vec.x * cos(alpha);     res.y = vec.y;     res.z = vec.z * cos(alpha) - vec.x * sin(alpha);     return (res); }  t_vec       z_rotation(t_vec vec, float alpha) {     t_vec   res;      res.x = vec.x * cos(alpha) - vec.y * sin(alpha);     res.y = vec.x * sin(alpha) + vec.y + cos(alpha);     res.z = vec.z;     return (res); } 

Werewolves in space?

We all know Werewolves are badass, that they can rip apart punny humans and mages and everything. They travel around the world on moon-bridges and through the Penumbra, ripping apart Pentax, Wyrm and Technocracy strongholds in the Tellurian and deep Umbra alike from within… But most rules regarding space are, afaik, in Mage books and I have not been diligent reading up on those (or all the Umbra stuff…)

So what if a Werewolf (or any Bête) for some reason sat in a mission to the ISS or even the moon? What happens then?! I mean, where do I find rules what changes for Werewolves in Space?!

Postgresql: Refreshing materialized view fails with “No space left on device” and a huge spike in disk usage

I have a materialized view that refreshes every five minutes. The SQL aggregates the data among many tables with over 800k rows in each.

However, the when using the "REFRESH MATERIALIZED VIEW CONCURRENTLY tableName", the query runs for about an hour and then complains: ERROR: could not write block 39760692 of temporary file: No space left on device

It should be noted that this 39760692 changes every time I execute the query.

The disk size is about 960 GB and the database size is about 30 GB. So the disk has a free space of about 930 GB.

I noticed that when running the refresh query, there is a huge spike in the disk usage of about 12GB per minute and then finally the query errors out with no space error when it hits the 960 GB mark. Immediately, the disk usage is back to 30GB from the abnormal growth.

I even tried the REFRESH MATERIALIZED VIEW tableName (without concurrently) and seeing the same behavior.

I’m not sure what can be done here to diagnose the problem.