Помогите сконфигурировать Spring.
Контроллер
@Controller @RequestMapping("/*") public class IndexController { private final Logger log = LoggerFactory.getLogger(this.getClass()); @RequestMapping(method = RequestMethod.GET) public String printHello(HttpServletRequest request, Model model) { ... Репозиторий
@Repository public class JpaRepositoryImpl implements JpaRepository { @PersistenceContext private EntityManager emf; // Для внедрения EntityManager ... ну и куча остальных нужных классов
Репозиторий подключен в spring-db.xml
... <bean id="emf" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="dataSource" ref="dataSource"/> <property name="jpaVendorAdapter" ref="jpaVendorAdapter"/> <property name="packagesToScan" value="ru.bityard.bitrix24.serverAuth.entities"/> </bean> ... Контроллер и сервисы подключены в spring-mvc.xml
... <context:component-scan base-package="ru.bityard.bitrix24.serverAuth.**.web"/> <context:component-scan base-package="ru.bityard.bitrix24.serverAuth.**.service"/> <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="prefix" value="/WEB-INF/jsp/"/> <property name="suffix" value=".jsp"/> </bean> ... Все остальные бины я собираю в spring-app.xml
И вот все это я пытаюсь собрать воедино в web.xml
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" version="3.1"> <display-name>Spring MVC Application</display-name> <context-param> <param-name>contextClass</param-name> <param-value> org.springframework.web.context.support.AnnotationConfigWebApplicationContext </param-value> </context-param> <context-param> <param-name>contextConfigLocation</param-name> <param-value> classpath:spring-app.xml classpath:spring-db.xml </param-value> </context-param> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <servlet> <servlet-name>index</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value> classpath:spring-mvc.xml </param-value> </init-param> <init-param> <param-name>throwExceptionIfNoHandlerFound</param-name> <param-value>true</param-value> </init-param> <init-param> <param-name>contextClass</param-name> <param-value> org.springframework.web.context.support.AnnotationConfigWebApplicationContext </param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>index</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app> Получаю ошибку:
2019-05-25 11:48:00 DEBUG http-nio-8080-exec-4:DispatcherServlet.java:doService:891 - DispatcherServlet with name 'index' processing GET request for [/index.php] 2019-05-25 11:48:00 DEBUG http-nio-8080-exec-4:AbstractHandlerMethodMapping.java:getHandlerInternal:312 - Looking up handler method for path /index.php 2019-05-25 11:48:00 DEBUG http-nio-8080-exec-4:AbstractHandlerMethodMapping.java:getHandlerInternal:322 - Did not find handler method for [/index.php] 2019-05-25 11:48:00 WARN http-nio-8080-exec-4:DispatcherServlet.java:noHandlerFound:1205 - No mapping found for HTTP request with URI [/index.php] in DispatcherServlet with name 'index' 2019-05-25 11:48:00 DEBUG http-nio-8080-exec-4:FrameworkServlet.java:processRequest:1000 - Successfully completed request Где у меня ошибка в конфигурации?
