Need to understand the refusal reasons of UK standard visit visa

I applied for UK standard visit visa (6 months) for tourism, and meeting cousin who lives there. The reasons of refusal they gave are attached in pictures.

Can you explain points 1 to 5? And it would be great if you can tell what I need to provide for each of them.

For point 1, I did not provide anything. What should I provide?

I assume I will have to re-apply now. Right?

Should I include documents again which I already provided earlier?

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I have a Schengen Visa, and I applied for UK visit visa from a country (not my national country). But it’s not the problem.

What’s the standard way to show downloading notification to user for file downloads that require authorization in web applications?

Our web application needs to enable secured file download by requiring HTTP requests to have authorization token.

Due to this, when user clicks download the file will be retrieved using AJAX GET request with the access token. Once the file is in memory, it will be saved to user’s hard drive using temporary link pointing to file’s data in memory.

Because of this approach, browser doesn’t show download progress immediately like in normal file download (in the bottom bar in Chrome). We need a way to tell user that something is going on as it may take some time to retrieve the file data.

We are thinking of showing a toast message and dismiss it when done. I haven’t seen many examples of this on the net in many websites.

What is the standard way (if there is any) to do this?

Return to UK as a tourist on multi entry business standard visitor visa

I hold a multi entry 6 month UK business visa (Standard Visitor Visa) and have already returned from the UK after the business trip.

The visa is still valid and I would like to return as a tourist.

Should I apply for tourist visa again? Or will I be allowed to enter the UK as a tourist.

I know I should ask the embassy but how do I get them to give me a written confirmation?

Explicit bivariate quadratic polynomials where Coppersmith is better than standard solver?

http://www.numbertheory.org/pdfs/general_quadratic_solution.pdf gives a general method to solve quadratic bivariate diophantine equation while Coppersmith introduced a method to solve bivariate polynomials which work provably and have been shown to break $ RSA$ system if half of low significant bits of either $ P$ or $ Q$ are known.

The equation that comes out is $ $ (2^ku+v)(2^ku’+v’)=PQ$ $ where if we assume $ v$ is known. Then $ vv’\equiv PQ\bmod 2^k$ gives $ v’$ .

So we have a quadratic diophantine equation $ $ 2^kuu’+(uv’+u’v)=\frac{PQ-vv’}{2^k}.$ $

Why do I need Coppersmith’s method to solve this? Can’t a regular diophantine solver work here and so are there explicit polynomials where Coppersmith is better than standard solver in bivariate quadratic case?

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Extension of Standard English Peg Solitaire

An entire analysis of standard English Peg Solitaire has been given. See

Berlekamp, E. R.; Conway, J. H.; Guy, R. K. (2001) [1981], Winning Ways for your Mathematical Plays (paperback) (2nd ed.), A K Peters/CRC Press, ISBN 978-1568811307.

Consider the standard English version of the game. The center peg is adjacent to the center-most peg of the left-most column of a $ 3 \times 3$ grid of pegs on the right, the center-most peg of the right-most column of a $ 3 \times 3$ grid of pegs on the left, and similar adjacency in the up and down directions from the center peg. I’m curious whether a variation of the game has been considered with, say, $ 2n+1 \times 2n+1$ grids in the four directions from the center peg? Many questions could be asked that were thoroughly answered for the standard game where $ n=1$ , like can jumps be made so that there is only one peg remaining? If so, how many ways are there to win both with and without symmetry? Obviously there are $ 4(2n+1)^2 -4 +1=16n^2+16n+1$ pegs in this variation.

Thanks for your time!

Below standard baby crib

Recently, I went to a hotel in Switzerland. I phoned weeks in advance to make sure they had a baby crib for my 5 month baby. They told me “Sure”.

When we arrived in the room, the crib was so old and worn that:

  • It was not level
  • Some metal pieces were showing out of the wood, presumably because some pieces covering them were missing. These pieces were close and sharp enough to hurt the baby (although not badly, probably)
  • It was shaky
  • It had drop sides, which is now prohibited in many places (but I could not find anything about where I was)

I complained and they sent someone with some tape and cloth to cover the metal parts and apologized, pretending that many unexpected kids arrived the night before.

I complained more, and they found another broken but modern crib somewhere. Together with my wife, we managed to fix it and baby slept well. The next day they changed the crib to a new one.

My question is:

Are up to standard baby cribs something I can ask for, complain about and make a big fuss about? If yes, what are my options if they don’t provide one? How can I pressure them to solve the problem?

Or is it more like little chocolates on the bed: something that the hotel is giving for free, and I should already be happy like that?

Given n standard C++ STL maps, can I merge them?

I was wondering if it is possible to merge standard STL maps in O(log(n)) using DSU trick.

For example, Map a={{1,2},{3,2},{4,3}}, Map b={{2,3},{3,2},{4,1}} and Map c={{2,1},{3,2},{4,4}}

Then the resultant map will be : {{1,2},{2,4},{3,6},{4,8}}

If not achieveable by DSU, is there any other algorithm to achieve this in O(logn) complexity?

Here n is the number of maps and the sum of the sizes of all maps is 10^5. n can range from 1-10^5.