Warning en consola de desarrollo de Google Chrome

Estoy desarrollando una página web con php y javascript, me sale el siguiente Warning y no entiendo a que se debe:

A cookie associated with a cross-site resource at was set without the SameSite attribute.

Y también muestra warning para jquery, highchart, google:

A cookie associated with a cross-site resource at http://google.com/ was set without the SameSite attribute.

A cookie associated with a cross-site resource at http://jquery.com/

¿Alguien tiene idea de que esta pasando?


When and how present a warning message when fields are not valid anymore?

I am working on a web app in which admin users can create forms, and editor users use those to create content. Admin can edit a form previously created and add warning validation based on specific content (determined by Regex).

Warning message workflow:

  1. Admin created an “ABC” form with a “DFE” field with no warning validation method.
  2. User A fills an “ABC” form (with title “ABC1”).
  3. Admin edit “ABC” form, assign a new warning validation to “DFE” field.
  4. User A edit the “ABC1” form.

Question: Although “ABC1” form field “DFE” was previously valid, it is now possibly not abiding by the new validation. If the field is not valid, when and how can we display the change that affects that field and its content?

Warning or error when incorrect number of checkboxes are selected

Good morning. I have a SharePoint list with a custom InfoPath form. One of the fields within that InfoPath form is a Choice field with checkboxes (multi-select). This field is not required, selecting none of the checkboxes is allowed. Selecting multiple checkboxes is also allowed, but selecting just one of the checkboxes is not allowed. How can we display an error or warning to the user completing the form that they must select more than one checkbox (or none at all)? If only one is selected a message should display that the field requires multiple items.

PROBLEMA CON CONEXCION PHP A MYSQL: Warning: mysqli_connect(): (HY000/1045): Access denied for user

tengo un problema conectando PHP a mi servidor MySQL usando el dominio.

<?php $  con = mysqli_connect('localhost', 'XXXXX', 'XXXXX'); if($  con){     echo 'Conexión exitosa con Localhost'; }else {     echo 'Conexión fallida con  Localhost'; } echo '</br>'; $  con1 = mysqli_connect('dominio.com', 'XXXXX', 'XXXXXX'); if($  con1){     echo 'Conexión exitosa con Dominio'; }else {     echo 'Conexión fallida con  Dominio'; }?> 

Esta es una prueba que hice DENTRO del servidor, donde se conecta tranquilamente si pongo Localhost, pero no se conecta si uso el dominio.

El resultado es:

Conexión exitosa con Localhost Warning: mysqli_connect(): (28000/1045): Access denied for user 

Esto es un problema porque realmente necesito pasar ese código a una aplicación externa que utiliza una conexión remota. Obviamente me he percatado una y otra vez de que estén bien escritos el usuario y la contraseña. También he agregado el nombre de la base de datos en la conexión. Además he intentando hacer la conexión remota añadiendo mi pc como anfitrión de acceso desde mi CPanel.

La verdad no sé qué demonios estoy haciendo mal jajaj. Agradezco su ayuda de antemano.

WARNING in Circular dependency detected: src\app\app.module.ts -> src\app\app.module.ngfactory.js -> src\app\app.module.ts

Tengo una aplicación con angular, y cuando intento

 ng build --prod 

Siempre sale

WARNING in Circular dependency detected: src\app\app.module.ts -> src\app\app.module.ngfactory.js ->  src\app\app.module.ts 

¿Por que sucede esto, y como puedo solucionarlo?

Muchas gracias por vuestra atención

libpng warning: Application jmp_buf size changed Segmentation fault when try to run xampp installation file

I trying to install XAMPP on my ubuntu 18.04 but I got this warning from libpng by running this command:

sudo ./xampp-linux-x64-7.3.9-0-installer.run 

The thing need to be considered is that I got this warning on all versions of XAMPP. Someone already asks the same question there libpng warning : Application jmp_buf size changed – while installing XAMPP but the answer is useless. Its a humble request please help.

Setpoint for warning

We have an induction stove, which has a glass surface that usually only gets hot by conduction from the pan you use on it. The control panel displays H when a burner is hot but not on. My experience is that the surface never gets hot enough to be a problem wiping up spills because the wipeup cloth provides enough insulation so I ignore the warning. Presumably there is a temperature sensor in the element and a threshold for displaying the H.

I was cooking potatoes tonight and spilled some of the oil as I was flipping them. The stove duly showed H on the burners that had oil on them. I got paper towels and wiped up the oil. It didn’t burn, but it was rather hot.

It got me thinking about the choice of a warning threshold. I can see the manufacturer wanting to make it low enough that nobody could get burned at the lowest temperature it comes on. That makes it low enough that people discover it is not a serious warning and ignore it. It seems like a standard problem that should have some standard thoughts about how you choose the threshold. What are they?