# Unexpected PDF in FirstPassageTimeDistribution

I am new to Markov Processes, and while learning the discrete Markov chain with the following matrix $$P=\begin{bmatrix}\frac{1}{3} & \frac{2}{3} & 0 & 0 \ \frac{1}{2} & \frac{1}{2} & 0 & 0 \ \frac{1}{4} & 0 & \frac{1}{4} & \frac{1}{2} \0 & 0 & 0 & 1\end{bmatrix},$$

I was told that $$f_{34}(n)=\left(\frac14\right)^{n-1}\frac12$$, where $$f_{ij}(n)$$ denotes the probability that starting in state $$i$$, we visit $$j$$ for the first time at time $$n$$. I can also verify this by hand.

I’ve tried the following input in Mathematica:

p = {{1/3, 2/3, 0, 0}, {1/2, 1/2, 0, 0}, {1/4, 0, 1/4, 1/2}, {0, 0, 0, 1}}; P = DiscreteMarkovProcess[3, p]; f34 = FirstPassageTimeDistribution[P, 4]; PDF[f34, n] 

But the result is $$\left\{\begin{array}{ll} 3 \times 4^{-n} & n>0 \0 & \text { True }\end{array}\right.$$

I’m confused since $$f_{34}(1)=p_{34}=\frac12$$, how can it be $$\frac34$$ as given? I’m using the version 12.1.1.0, could anyone give me a hint where I went wrong? Thanks!