\begin{align*} \sin x- 5\cos x & = 0\ \tan x\frac{\sin x}{\tan x}-5\frac{\sin x}{\tan x} & =0\ \sin x(\tan x- 5) & =0 \end{align*}

I think it has something to do with my writing $ \cos x$ as $ \frac{\sin x}{\tan x}$

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# What is wrong with my solution to this trigonometric equation: $\sin x – 5\cos x = 0$?

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I think it has something to do with my writing $ \cos x$ as $ \frac{\sin x}{\tan x}$

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