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Can I drag a grappled creature and release it after moving half of my speed, then move the remainder of my speed?

The grappling rules state:

Moving a Grappled Creature.

When you move, you can drag or carry the grappled creature with you, but your speed is halved, unless the creature is two or more sizes smaller than you.

If I have 30 speed and have an enemy grappled, then I move 15 feet and release my grapple on my target, do I still have 15 feet of movement left, or is it lost for the round?

How to speed up an insertion from a huge table with postgres?

I have 5 tables in my database with respectively a size of 70Gb, 500Mb, 400 Mb, 110Mb and 20 Mb.

I want to create a new table that contains all columns of all tables, so I tried 2 queries, the first one is :

select into new_table as select .. from t1 join t2 join t3 join t4 ... 

and the second one is :

insert into new_table select .. from t1 join t2 join t3 join t4  ... 

Before executing these two queries on my big data tables, I tried both on a total 1G database, the first on took only 7s and the second one approximately 10 mn.

Now, executing the first one on my huge database, made my disk full even though I had 250Gb free space before running the query, and without finishing the query so I got the follow error :

ERROR:  could not write to temporary file: No space left on device 

The second one, is taking a lot of time and consuming my free disk space slowly and, as the first one, not returning the result.

What are the difference between these two queries ? Is there a way to make the insert into non transactional so as I can follow my insert steps. And I guess Postgres uses logs (journalization) so is there a way to deactivate that in order to speed up the insertion ? or I should follow another method in order to get a desired result without filling up all disk

When reverting back to humanoid after being polymorphed, can a character have remaining movement speed in that turn?

A hag transforms my character into a frog, which gives my character a movement speed of 20 feet. Let’s say that as a humanoid I would have had a speed of 30 feet instead. I use the frog’s full movement, before the hag uses a reaction to strike me with an Attack of Opportunity.The hit does nough damage to revert back to my original form.

Do I now have 10 feet of movement remaining this turn, since I only used up 20 of my maximum speed?

Related

How do changes to your speed affect your available movement?

This question doesn’t answer my question, since it doesn’t a) give a clear yes or no to my question, and b) specifically address the context of having different shapes during a turn.

How to speed up the calculation of the number of 4 * 4 Young tableaux

I find the problem of calculating n * n Young tableaux from here. I can get the number of 3*3 Young tableaux by violent enumeration is 42:

Partition[#, 3] & /@    Select[Permutations[     Range[9]], ((#[[2]] > #[[1]]) && (#[[3]] > #[[2]]) && (#[[5]] > \ #[[4]]) && (#[[6]] > #[[5]]) && (#[[8]] > #[[7]]) && (#[[9]] > \ #[[8]]) && (#[[1]] < #[[4]]) && (#[[1]] < #[[4]]) && (#[[4]] < \ #[[7]]) && (#[[2]] < #[[5]]) && (#[[5]] < #[[8]]) && (#[[3]] < \ #[[6]]) && (#[[6]] < #[[9]])) &] // Length 

But in the case of 4 * 4, the calculation speed of my algorithm below is very slow. How can I modify it to improve the calculation speed?

Needs["Combinatorica`"] s = {}; k = 0; rule = ((#[[1]] < #[[2]]) && (#[[2]] < #[[3]]) && (#[[3]] < #[[4]]) \ && (#[[5]] < #[[6]]) && (#[[6]] < #[[7]]) && (#[[7]] < #[[8]]) && \ (#[[9]] < #[[10]]) && (#[[10]] < #[[11]]) && (#[[11]] < #[[12]]) && \ (#[[13]] < #[[14]]) && (#[[14]] < #[[15]]) && (#[[15]] < #[[16]]) && \ (#[[1]] < #[[5]]) && (#[[5]] < #[[9]]) && (#[[9]] < #[[13]]) && \ (#[[2]] < #[[6]]) && (#[[6]] < #[[10]]) && (#[[10]] < #[[14]]) && \ (#[[3]] < #[[7]]) && (#[[7]] < #[[11]]) && (#[[11]] < #[[15]]) && \ (#[[4]] < #[[8]]) && (#[[8]] < #[[12]]) && (#[[12]] < #[[16]])) &;  For[i = 1, i <= 16! - 1, i++,   If[MatchQ[Combinatorica`NthPermutation[i, Range[16]], _?(rule)],    k++;]] k 

Is the “half your speed” used in standing from prone your normal speed, or current speed?

At my last session, a scenario arose in which a character was attempting to cover ground as quickly as possible, but was knocked prone. On their next turn, they proceeded to stand up and Dash. This led to a moment of confusion while I attempted to figure out exactly how prone and Dash interact.

The player commented offhand that standing from prone halves your movement and Dash doubles it, so the two cancel and they had 30ft to move that turn. Reading the rules, however, I interpreted things differently.

Dash

When you take the Dash action, you gain extra movement for the current turn. The increase equals your speed, after applying any modifiers. With a speed of 30 feet, for example, you can move up to 60 feet on your turn if you dash.

Any increase or decrease to your speed changes this additional movement by the same amount. If your speed of 30 feet is reduced to 15 feet, for instance, you can move up to 30 feet this turn if you dash.

(PHB p192)

Being Prone

[…] You can drop prone without using any of your speed. Standing up takes more effort; doing so costs an amount of movement equal to half your speed. For example, if your speed is 30 feet, you must spend 15 feet of movement to stand up.

(PHB p190)

My interpretation is that your speed is constant – say, 30ft – and your movement is a separate quantity representing distance you can cover this turn. You start the turn with available movement equal to your speed, and then Dash adds another quantity to your movement, while standing up removes a quantity from your movement. Neither affect your speed.

That means that this player starts with 30ft of movement, gains an additional amount equal to their speed (30ft) from Dash, then spends an amount equal to half their speed (30/2 = 15ft) to stand, leaving them with 45ft of movement available for this turn.

In the end, they needed less than 30ft of movement to get into position to attack the bandit leader and the party all made it out alive, so it didn’t affect the outcome of our game, but I’d like to get this straightened out for the future.

Is my interpretation of the interaction between speed, movement, the prone condition and the Dash action correct?

Flying movement: does minimum forward speed still apply when ascending?

I’ve worded the question in two ways, before and after context, both bolded text below.

Let’s say you have some fly speed with average maneuverability. Speed is not important. You have a minimum forward speed (MFS) of half, an up angle of 60 degrees, and an up speed of half. Imagine you begin ascending. Aside from beginning your ascent (where you have to fly steady for half maximum distance before ascending), does MFS still apply if you continue ascending the next round? If minimum forward speed applies when ascending (moving at your “up speed”), then implicitly you need a full double move to ascend at the full 60 degrees, and in general you cannot ascend at 60 degrees (math below).

For 60 degrees, the standard trig triangle has a hypotenuse of 2 and a base of 1. In D&D terms, however far you fly at 60 degrees, you fly half that distance forward. Therefore, if your up speed is half, flying half your speed at 60 degrees means you fly only one-quarter your speed forward, which doesn’t meet the minimum forward speed of half requirement.

It’s not hard to see that flying at 60 degrees under this logic requires a double move, and you must use all your movement to achieve the minimum forward speed (a double move at half speed is full speed along 60 degrees, which means you moved half speed forward).

Otherwise for a single move action, you’re capped at much smaller angles of ascension, if that’s even technically possible within the rules. For example, with a fly speed of 60 and average maneuverability, you could still move foward 30 and up 15. Again, it doesn’t really say whether or not you can ascend at lower angles, but I wouldn’t see why not.

So, is this implicit logic correct, or is ascension supposed to be a different mode of movement whereby minimum forward speed shouldn’t apply?

Can’t Understand the formula for processing speed of each job

I am trying to understand the formula for processing speed of each job. I got the formula from the following link:

Fair Online Scheduling for Selfish Jobs on Heterogeneous Machines

The other details are provided below:

Description1

I can’t understand what is the basis (i.e. the fundamental logic) of the following formula. Speed (i.e. Velocity) is given by : S= V * t

Why we have this fraction term in the formula? What does the denominator represent? I think it is representing the processing time of each job.

Somebody please guide me

Description 2

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